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MAVERICK [17]
3 years ago
5

I have an algorithm that runs in O(N ), where N is the size of the problem. For N = 100, the time for the algorithm to run is 1

minute. How long does the algorithm take for N=1000? A) Same time B) 10 minutes C) 100 minutes D) 1000 minutes
Physics
1 answer:
hodyreva [135]3 years ago
4 0

Answer:

B) 10 minutes

Explanation:

When the size of the problem is 100 then it takes 1 minute to solve

100\ s=1\ min

So, when the size of the problem is 1 then it takes the following minutes

1\ s=\frac{1}{100}\ min

For when the size of the problem is 1000 we have

1000\ s=\frac{1000}{100}\ min=10\ min

So, it will take 10 minutes to solve the algorithm of size 1000

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A

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A person is riding a motorized tricycle. They weigh 180kg and are moving at 3 m/s over a distance of 300 m. How much work is don
agasfer [191]

If I am to understand this question correctly this is what asks you:

If a person is riding a motorized tricycle how much work do they do?

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3 0
3 years ago
A silver wire 2.6 mm in diameter transfers a charge of 420 C in 80 min. Silver contains 5.8 x 10- free electrons per cubic meter
kifflom [539]

Answer:

a). 87.5 mA or 87.5 x10^{-3}A

b). 1.78 \frac{m}{s}

Explanation:

d=2.6 mm \\Q=420C\\t=80min\\n=5.8x10^{28} \\q=1.6x10^{-19}

n the number of free electrons is 28 in text reference and if they don't give q is take as the charge of electron.

a).

I=\frac{Q}{t}\\ I= \frac{420 C}{80 min}*\frac{1min}{60 s} =\frac{420 C}{4800s}\\  I=87.5 x10^{-3}A

b).

I=n*abs (q)*V_{d}*A

A= \pi * (\frac{d}{2})^{2} \\A=\pi (*\frac{2.6x10^{-3} m}{2})^{2}  \\A=5.309x10^{-6}

V_{d} =\frac{I}{n*abs(q)*A} \\V_{d}=\frac{87.5 x10^{-2} }{5.8x^10{28} *1.6x^{-19} *5.3x^{6} }\\V_{d}=1.78 \frac{m}{s}

8 0
3 years ago
give an example of motion in which displacement of the particle is zero but acceleration is not zero in journey?
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Motion of a ball thrown by a person upwards and caught after some time is an example of motion in which displacement of the particle is zero but acceleration is not zero in journey.

The displacement of the ball is zero because the starting and end point of the motion are same, i.e, the person's hands.During its motion, the acceleration of ball is constant and non zero called as acceleration due to gravity, g= -9.8 m/s². The velocity of ball is continuously changing. It first decreases during the upward motion of the ball and then increases during the downward journey.The acceleration remains constant and non zero all the time.

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