Answer:
T is less than or equal to 19 N
Explanation:
Answer: 5.72 x 10-3Ω
Explanation:
Hi, to answer this question, first we have to calculate the cross sectional area of the cable:
Diameter (D)=6.07 mm
Since: 1000mm = 1m
6.07mm/ 1000mm/m = 0.00607 meters
Area of a circle : π (d/2)^2
A = π (0.00607/2)^2= 0.000028937 m2
Resistance formula:
Resistance (R) = P(resistivity) L (length)÷A (cross sectional area )
Replacing with the values given:
R = (2.82x10-8 x 5.87) / 0.000028937
R = 5.72 x 10-3Ω
Feel free to ask for more if needed or if you did not understand something.
I think the answer for the question above its b 1.2
Answer:
Therefore % increase in velocity is 18.23 %
Explanation:
we use the equality of mass flow rate and the areas
The percentage increase in velocity is
Δ v% = 
100%
= 
.100%
= 
. 100%
= Therefore % increase in velocity is 18.23 %
Answer:
C. 3.00 s
Explanation:
Given:
Δy = 1.80 m − 46.0 m = -44.2 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
-44.2 m = (0 m/s) t + ½ (-9.8 m/s²) t²
t = 3.00 s
