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JulsSmile [24]
4 years ago
5

Describe the difference between potencial and kinetic energy

Physics
1 answer:
avanturin [10]4 years ago
8 0
Potential energy is energy stored in an object. kinetic energy is energy of motion
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The solar system is really big! To give you an idea of its dimensions, think that if the Sun was Washington DC and Mercury was t
12345 [234]

The sun is the center of the solar system which is surrounded by the nine planets and they tend to orbit the sun in concentric circles with the sun as the center.

<h3>What is the solar system?</h3>

The term solar system has to do with the arrangement of the sun and the planets. The sun lies at the focus of the solar system. Now we know that there are nine planets that orbit around the sun. The distance between the planets and the sun depends on their relative proximity to each other.

Thus, the sun is the center of the solar system which is surrounded by the nine planets and they tend to orbit the sun in concentric circles with the sun as the center.

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8 0
2 years ago
What is the formula for the moment of inertia of the person/single particle rotating in a circle? (Give these values with a subs
Ann [662]

Moment of inertia of single particle rotating in circle is I1 = 1/2 (m*r^2)

The value of the moment of inertia when the person is on the edge of the merry-go-round is I2=1/3 (m*L^2)

Moment of Inertia refers to:

  • the quantity expressed by the body resisting angular acceleration.
  • It the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.

The moment of inertia of single particle rotating in a circle I1 = 1/2 (m*r^2)

here We note that the,

In the formula, r being the distance from the point particle to the axis of rotation and m being the mass of disk.

The value of the moment of inertia when the person is on the edge of the merry-go-round is determined with parallel-axis theorem:

I(edge) = I (center of mass) + md^2

d be the distance from an axis through the object’s center of mass to a new axis.

I2(edge) = 1/3 (m*L^2)

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7 0
2 years ago
7. Katie and her best friend Liam play tennis every Saturday morning. When Katie serves the ball to Liam, it
KIM [24]

a. 4.52 m/s south

Velocity is a vector, whose magnitude is defined as the ratio between the displacement of the object and the time taken for the displacement to occur:

v=\frac{d}{t}

where

d is the displacement

t is the time

Velocity is a vector, so it also has a direction, which corresponds to that of the displacement.

For the ball in this problem,

d = 9.5 m south

t = 2.1 s

Substituting, we find:

v=\frac{9.5}{2.1}=4.52 m/s

and the directiion is the same as the displacement (south).

b. 4.52 m/s north

For this part, we must keep in mind that the speed is the magnitude of the velocity; however, speed is a scalar, so it does not have a direction.

Here we are told that the tennis ball travels at constant speed, so on its way back from Liam to Katie the ball's velocity is still the same as before, therefore

|v| = 4.52 m/s

However, this time the direction is opposite to before, since the ball is travelling in the opposite direction.

Therefore, the ball's velocity when Liam returns Katie's service is

4.52 m/s north

8 0
3 years ago
identify the Transformations that take place when you use an electric heater. begin with the transformations that take place in
galben [10]
It is a electrical change
3 0
4 years ago
Suppose the space shuttle is in orbit 300 km from the Earth's surface, and circles the earth about once every 90
Valentin [98]

The centripetal acceleration of the space shuttle is 9.0 m/s^2 (0.9g)

Explanation:

The period of revolution of the space shuttle is

T=90 min \cdot 60 = 5400 s

From the period, we can calculate the angular speed of the space shuttle, which is given by

\omega = \frac{2\pi}{T}=\frac{2\pi}{5400}=1.16\cdot 10^{-3} rad/s

Now we can calculate the centripetal acceleration of the space shuttle, given by

a=\omega^2 r

where

\omega=1.16\cdot 10^{-3} rad/s is the angular speed

r=6.40 \cdot 10^6 m +300\cdot 10^3 m = 6.7\cdot 10^3 m is the distance of the shuttle from the Earth's centre (it is the  sum of the Earth's radius, 6400 km, and of the altitude of the space shuttle, 300 km)

Substituting and solving, we find

a=(1.16\cdot 10^{-3})^2(6.7\cdot 10^6)=9.0 m/s^2

And since g=9.8 m/s^2, this can be rewritten as

a=\frac{9.0}{9.8}=0.9g

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7 0
3 years ago
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