2 answers:
Answer:
A or B
<em><u>(a) is always at +ve potential.</u></em>
<em><u>(b) is always at zero potential.</u></em>
Explanation:
<em><u>reason </u></em>
- <em><u>a </u></em><em><u>conductor</u></em><em><u> </u></em><em><u>with </u></em><em><u>positive</u></em><em><u> </u></em><em><u>charge </u></em><em><u>is </u></em><em><u>always </u></em><em><u>positive</u></em><em><u> </u></em><em><u>and </u></em><em><u>zero </u></em><em><u>potential</u></em>
<em><u>h</u></em><em><u>ope </u></em><em><u>it's</u></em><em><u> helpful</u></em>
Answer:
B
Explanation:
Let's see the formula
If q is positive it yeilds V or potential as positive hence it is at zero potential
Option B is correct
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