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2 years ago

Hello people~

Physics

2 answers:

Wewaii [24]2 years ago

5 0

Answer:

A or B

(a) is always at +ve potential.

(b) is always at zero potential.

Explanation:

reason 

a conductor with positive charge is always positive and zero potential

hope it's helpful

galina1969 [7]2 years ago

4 0

Answer:

Explanation:

Let's see the formula

V=kq/r

If q is positive it yeilds V or potential as positive hence it is at zero potential

Option B is correct

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Select the correct answer.

Pepsi [2]

Answer:

B. 2 hours

Explanation:

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3 years ago

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A temperature of 200 degrees F is equivalent to approximately

Ann [662]

(1) Changing Fahrenheit to Celsius:
The formula used to convert from Fahrenheit to Celsius is as follows:
C = (F - 32) * 5/9
We are given that F=200, substitute in the above formula to get the corresponding temperature in Celsius as follows:
C = (200-32) * (5/9) = 93.333334 degrees Celsius

(2) Changing the Fahrenheit to kelvin:
The formula used to convert from Fahrenheit to kelvin is as follows:
K = (F - 32) * 5/9 + 273.15
We are given that F = 200. substitute in the above formula to get the corresponding temperature in kelvin as follows:
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3 years ago

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A stoplight with weight 100 N is suspended at the midpoint of a cable strung between two posts 200 m apart. The attach points fo

Tasya [4]

There are 3 forces acting on the stoplight:

• its weight W, with magnitude W = 100 N, pointing directly downward

• two tension forces T₁ and T₂ with equal magnitude T₁ = T₂ = T = 1000 N, both making an angle of θ with the horizontal, but one points left and the other points right

The stoplight is in equilibrium, so by Newton's second law, the net vertical force acting on it is 0, such that

∑ F = T₁ sin(θ) + T₂ sin(180° - θ) - W = 0

We have sin(180° - θ) = sin(θ) for all θ, so the above reduces to

2T sin(θ) = W

2 (1000 N) sin(θ) = 100 N

sin(θ) = 0.05

θ ≈ 2.87°

If y is the vertical distance between the stoplight and the ground, then

tan(θ) = (15 m - y) / (100 m)

Solve for y :

tan(2.87°) = (15 m - y) / (100 m)

y = 15 m - (100 m) tan(2.87°)

y ≈ 9.99 m

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3 years ago

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3 years ago

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A projectile is launched with an initial velocity of (40 m/s), at an angle of (30°) above

zlopas [31]

Answer:

330.5 m

Explanation:

In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .

The maximum height will be calculated as;

$h=\frac{v^2_isin^2\alpha }{2g}$

where ∝ is the angle of launch = 30°

vi= initial launch velocity = 40 m/s

g= 10 m/s²

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h={1600*0.4132 }/ 20

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2 years ago