If I have an object that starts from rest and reaches a velocity of 25m/s over a distance of 11m what is the acceleration of the
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Answer:
8.8 m and 52.5 m
Explanation:
The vertical component and horizontal component of water velocity leaving the hose are
Neglect air resistance, vertically speaking, gravitational acceleration g = -9.8m/s2 is the only thing that affects water motion. We can find the time t that it takes to reach the blaze 10m above ground level
t = 3.49 or t = 0.58
We have 2 solutions for t, one is 0.58 when it first reach the blaze during the 1st shoot up, the other is 3.49s when it falls down
t is also the times it takes to travel across horizontally. We can use this to compute the horizontal distance between the fire-fighters and the building
The kinematic equations are used to <span>quantify motion in the case of uniform acceleration.
The other name is : SUVAT equations, where the letters signify:
displacement (s),
initial velocity (u),
final velocity (v),
acceleration (a), and
time (t).
There are three equations are attached in the picture: </span>
The other name is : SUVAT equations, where the letters signify:
displacement (s),
initial velocity (u),
final velocity (v),
acceleration (a), and
time (t).
There are three equations are attached in the picture: </span>