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aleksandrvk [35]
3 years ago
15

Use the drop-down menus to identify each labeled part of the diagram.

Physics
1 answer:
iren2701 [21]3 years ago
3 0

Answer:

<u>A:cool fluid sinks</u>

<u>B:warm fluid rises</u>

<u>C:convection current</u>

Explanation:

Just took the assessment!!

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When you strike two tuning forks simultaneously, you hear three beats per second. The frequency of the first tuning fork is 440
tekilochka [14]

Answer:4

Explanation:

Given

Frequency of beats is 3 beats per second

Frequency of first tuning fork is f_1=440\ Hz

Beat frequency is difference in the frequency of tuning forks i.e.

either f_1-f_2 or f_2-f_1 =3

so f_2=3+440=443\ Hz

or

f_2=440-3=437\ Hz

so there is not enough information given to decide.

5 0
3 years ago
Read 2 more answers
10. As a spaceship is moving toward Earth, an Earthling measures its length to be 325 m, while the captain on board radios that
Oliga [24]

Answer:

Explanation:

10. As a spaceship is moving toward Earth, an Earthling measures its length to be 325 m, while the captain on board radios that her spaceship's length is 1150 m. (c = 3.00 × 108 m/s) (a) How fast is the rocket moving relative to Earth? (b) What is the TOTAL energy of a 75.0-kg crewman as measured by (i) the captain in the rocket and (ii) the Earthling?

3 0
2 years ago
A cylinder is fitted with a piston, beneath which is a spring, as in the drawing. The cylinder is open to the air at the top. Fr
astraxan [27]

Answer:

x =  0.0734 m = 7.34 cm

Explanation:

First we shall calculate the area of the piston:

Area = \pi radius^2\\Area = \pi (0.028\ m)^2\\Area = 0.00246\ m^2

Now, we will calculate the force on the piston due to atmospheric pressure:

Atmospheric\ Pressure = \frac{Force}{Area}\\\\Force = (Atmospheric\ Pressure)(Area)\\Force = (101325\ N/m^2)(0.00246\ m^2) \\Force = F = 249.56\ N

Now, for the compression of the spring we will use Hooke's Law as follows:

F = kx\\

where,

k = spring constant = 3400 N/m

x = compression = ?

Therefore,

<u>x =  0.0734 m = 7.34 cm</u>

8 0
3 years ago
Supposing you were in space..in a weightless environment, would it require a force to set an object in motion? Explain..
Dvinal [7]

Answer:

Yes, a force is require to set an object in motion.

Explanation:

  • In space, even if you feel weightless, you are subject to motion. If you are orbiting the Earth, you are under the constant influence of Earth having a free-fall acceleration equal to the centripetal acceleration.
  • To disturb this orbital motion, an external force is required.
  • According to Newton's laws of motion, a force is required to change the state of the rest of a body or to change the velocity or direction if it is moving with uniform velocity along a straight line.
  • Whenever there is a change in velocity or direction of a body there is a force acting on it.
8 0
3 years ago
How do we move in space without any friction?
Luba_88 [7]

Answer:

The Physical Behavior of Objects when Gravity is Missing

In order to be able to form a concept of the general physical conditions existing in a weightless state, the following must be noted: the force of the Earth's gravity pulling all masses down to the ground and thus ordering them according to a certain regularity is no longer active.

4 0
3 years ago
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