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Ganezh [65]
3 years ago
13

How to solve b(5px-3c)=a(qx-4) for x

Mathematics
1 answer:
dsp733 years ago
8 0
We want to determine x from the expression
b(5px - 3c) = a(qx - 4)

Expand each side.
5bpx - 3bc = aqx - 4a

Subtract aqx from each side.
5bpx - aqx - 3bc = - 4a
x(5bp - aq) - 3bc = - 4a

Add  3bc to each side.
x(5bp - aq) = 3bc - 4a

Divide each side by 5bp - aq
x = (3bc - 4a)/(5bp - aq)

Answer:  x= \frac{3bc-4a}{5bp-aq}

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seropon [69]
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3 years ago
What must be subtracted from 4x4 - 2x3 -6x2 + x - 5 so that the result is exactly divisible by 2x2 + 3x - 2? PLS ANSWER. I WILL
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Answer:

Step-by-step explanation:

To solve this we should use the Euclidean division :

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Here is a picture with the operation

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