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10 months ago

Which physical method can be used for obtaining a sample of salt from a sm

1 answer:

6 0

The physical method that can be used for obtaining a sample of salt from a small beaker of salt and water would be evaporation.

<h3>Separation of salt and water</h3>

A mixture of salt and water can be separated by a method known as evaporation. This is based on the assumption that the salt in question is a water-soluble salt.

In order to separate the salt/water mixture:

Place the mixture in a suitable evaporating dish
Boil the mixture until all the water evaporates.
The remaining residue would be the salt

Care should be taken not to overheat the residue in order to avoid melting. Evaporation is generally used to separate a mixture of water and soluble salt. If the salt is insoluble, filtration using a suitable filter paper will filter off the salt while the water is collected as the filtrate.

More on evaporation can be found here: brainly.com/question/1097783

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Which physical method can be used for obtaining a sample of salt from a small beaker of salt water?

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Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions.

sammy [17]

A electrochemical reaction is said to be spontaneous, if $E^{0} cell is positive.$

Answer 1:
Consider reaction: <span>Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s)

The cell representation of above reaction is given by;
  </span> $S^{2-}/S // Ni^{2+}/Ni$

Hence, $E^{0}cell = E^{0} Ni^{2+/Ni} - E^{0} S/S^{2-}$
we know that, ${E^{0} Ni^{2+}/Ni = -0.25 v$
and ${E^{0} S/ S^{2-} = -0.47 v$

Therefore, $E^{0} cell$ = - 0.25 - (-0.47) = 0.22 v

Since, $E^{0} cell$ is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2:
Consider reaction: <span>Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)
</span>
The cell representation of above reaction is given by;
   $H_{2} / H^{+} // Pb^{2+} /Pb$

Hence, $E^{0}cell = E^{0} Pb/Pb^{2+} - E^{0} H_{2}/H^{+}$
we know that, ${E^{0} Pb^{2+}/Pb = -0.126 v$
and ${E^{0} H_{2}/ H^{+} = -0 v$

Therefore, $E^{0} cell$ = - 0.126 - 0 = -0.126 v

Since,   $E^{0} cell$ is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3:
Consider reaction: <span>2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)
</span>
The cell representation of above reaction is given by;
   $Cr/Cr^{2+} // Ag^{+}/Ag$

Hence, $E^{0}cell = E^{0} Ag^{+}/Ag - E^{0} Cr/Cr^{2+}$
we know that, ${E^{0} Ag^{+}/Ag = -0.22 v$
and ${E^{0} Cr/ Cr^{2+} = -0.913 v$

Therefore, $E^{0} cell$ = - 0.22 - (-0.913) = 0.693 v

Since,   $E^{0} cell$ is positive, hence cell reaction is spontaneous

8 0

3 years ago

Read 2 more answers

There are seven major levels of classification. Kingdom and Phylum are just two of the levels. Which of the following are also m

kumpel [21]

A) The class and C) Family would be the only accurate option. Here are the levels from largest to smallest: <span>kingdom, phylum, class, order, family, genus and species.</span>

7 0

3 years ago

a solution of prepared by dissolving 20.0 brams of mavni fluride (MgF2) in 80.0 of water (H2O). whag is the mole fraction of mag

Serjik [45]

Answer:

2000.1234 trebuie sa fie asa

3 0

3 years ago

The following are steps in the process of cloning a mouse. Arrange the steps in the correct order. (8.L.2.1) *

andrezito [222]

Answer:

Explanation:

I got A wrong so maybe

8 0

2 years ago

2) Two students are running in a cross country race. One has a mass of 60 kg, while the other has a mass of 70 kg. If they are b

Iteru [2.4K]

Answer:

The second student with mass 70kg has more momentum

Explanation:

Using the formula:

p = m × v

Where;

p = momentum (kgm/s)

m = mass (kg)

v = velocity (m/s)

According to this question, two students are running in a cross country race.

Student 1 has the following; m = 60kg, v = 7m/s

Student 2 has the following; m = 70kg, v = 7m/s

Using p = mv

Student 1, p = 60 × 7 = 420 kgm/s

Student 2, p = 70 × 7 = 490 kgm/s

From the result of the above calculations, student 2 with mass 70kg has more momentum.

4 0

2 years ago