Empirical formula is the simplest ratio of whole numbers of components in a compound
in 100 g of compound
C H O
mass 25.5 g 6.40 g 68.1 g
number of moles 25.5 g/12 g/mol 6.40 g/ 1 g/mol 68.1 g/ 16 g/mol
= 2.13 mol = 6.40 mol = 4.26 mol
divide by least number of moles
2.13/2.13 = 1 6.40/2.13 = 3.0 4.26/2.13 = 2.0
all rounded off
C - 1
H - 3
O - 2
empirical formula - CH₃O₂
- low conductivity
- generally non-toxic
- ductile
- doesn’t corrode as fast as other metals
The number of moles of a gas if it occupy a volume of 4dm at 10 atm and - 200 c is 6.67 moles
calculation
by use of ideal gas equation
that is PV =nRT
where P(pressure) = 10 atm
V( volume) = 4dm^3 = 4L
n(number of moles) =?
R(gas constant) = 0.0821 L.atm/mol.K
T = -200 +273 = 73 K
make n the formula of the subject n = PV/RT
n is therefore = (10 atm x 4l)/(0.0821 L.atm/mol.K x 73 K) = 6.67 moles
Answer:
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Explanation:
hope it will help you
The most abundant isotope among the given Isotopes will be Isotope B
<h3>How to calculate percentage abundance of isotopes ?</h3>
To calculate the percent abundance of each isotope in a sample of an element, we usually divide the number of atoms of a particular isotope by the total number of atoms of all isotopes of that element and then multiply the result by 100.
% Abundance = 15/50 x 100
= 30 %
% Abundance = 30/50 x 100
= 60 %
% Abundance = 5/50 x 100
= 10 %
Hence, The most abundant isotope among the given Isotopes will be Isotope B.
Learn more about isotopes here ;
brainly.com/question/12955625
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