If the [H+] in a solution is 1 × 10–1 mol/L, what is the [OH

A gas balloon has a volume of 80.0 mL at 300K, and a pressure of 50.0 kPa. If the pressure changes to 80 kPa and the temperature

fomenos

Answer: The new volume is 53.3 ml

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 50.0 kPa

$P_2$ = final pressure of gas = 80.0 kPa

$V_1$ = initial volume of gas = 80.0 ml

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $300K$

$T_2$ = final temperature of gas = $320K$

Now put all the given values in the above equation, we get:

$\frac{50.0\times 80.0}{300}=\frac{80.0\times V_2}{320}$

$V_2=53.3ml$

The new volume is 53.3 ml

4 0

3 years ago

A hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

kupik [55]

hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.

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6 0

3 years ago

Helium decays to form lithium. Which equation correctly describes this decay?

GrogVix [38]

Answer:

⁴He₂ → ⁴Li₃ + ⁰e₋₁.

Explanation:

Helium decays with the release of an electron to form a lithium nucleus.

The number of nucleons is the same on both sides of the equation.

A neutron decays to form a proton with the release of an electron.

The atomic number increases from 2 to 3 while the atomic mass number stays the same at 4 nucleons.

8 0

3 years ago

Read 2 more answers

Atoms of two different elements must have different

attashe74 [19]

Atomic number The atomic number of each element is different than other Elements.

8 0

3 years ago

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The solvent is usually referred to as the component of a solution which is present as

Eddi Din [679]

The solvent is usually referred to as the component of a solution which is present as the one with the larger quantity and in most cases as the liquid which dissolves a solid. In a solution, there are two components namely the solvent and the solute. The solute is the one in smaller amount.

8 0

3 years ago

Read 2 more answers

If the [H+] in a solution is 1 × 10–1 mol/L, what is the [OH–]? Show your work.