All categories

2 years ago

Age, height, and weight are examples of numerical data.

Physics

2 answers:

Andrej [43]2 years ago

7 0

Answer:

True

Explanation:

Examples of numerical data are height, weight, age

Darya [45]2 years ago

4 0

Yes there are examples of numerical data are height, weight age

You might be interested in

A generator with �# ' = 300 V and Zg = 50 Ω is connected to a load ZL = 75 Ω through a 50-Ω lossless line of length l = 0.15λ. (

ki77a [65]

Answer:

a. Zin = 41.25 - j 16.35 Ω

b. V₁ = 143. 6 e⁻ ¹¹ ⁴⁶

c. Pin = 216 w

d. PL = Pin = 216 w

e. Pg = 478.4 w , Pzg = 262.4 w

Explanation:

Zin = Zo * [ ZL + j Zo Tan (βl) ] / [ Zo + j ZL Tan (βl) ]

βl = 2π / λ * 0.15 λ = 54 °

Zin = 50 * [ 75 + j 50 Tan (54) ] / [ 50 + j 75 Tan (54) ]

Zin = 41.25 - j 16.35 Ω

I₁ = Vg / Zg + Zin ⇒ I₁ = 300 / 41.25 - j 16.35 = 3.24 e ¹⁰ ¹⁶

V₁ = I₁ * Zin = 3.24 e ¹⁰ ¹⁶ * ( 41.25 - j 16.35)

V₁ = 143. 6 e⁻ ¹¹ ⁴⁶

Pin = ¹/₂ * Re * [V₁ * I₁]

Pin = ¹/₂ * 143.6 ⁻¹¹ ⁴⁶ * 3.24 e ⁻ ¹⁰ ¹⁶ = 143.6 * 3.24 / 2 * cos (21.62)

Pin = 216 w

The power PL and Pin are the same as the line is lossless input to the line ends up in the load so

PL = Pin

PL = 216 w

Pg Generator

Pg = ¹/₂ * Re * [ V₁ * I₁ ] = 486 * cos (10.16)

Pg = 478.4 w

Pzg dissipated

Pzg = ¹/₂ * I² * Zg = ¹/₂ * 3.24² * 50

Pzg = 262.4 w

4 0

4 years ago

A 4.50-volt personal stereo uses 1950 joules of electrical energy in one hour. what is the electrical resistance of the personal

saveliy_v [14]

The stereo uses an energy of $E=1950 J$ in a time $t=1 h=3600 s$ , therefore the power of the stereo is given by
$P= \frac{E}{t}= \frac{1950 J}{3600 s}=0.54 W$

We also know that the power of an electrical device is related to its voltage, V, and its resistance, R, by the following equation
$P= \frac{V^2}{R}$
therefore, we can rearrange the equation to calculate the resistance of the stereo:
$R= \frac{V^2}{P}= \frac{(4.5 V)^2}{0.54 W}=37.5 \Omega$

6 0

4 years ago

A 4000-kg car bumps into a stationary 6000kg truck. The Velocity of the car before the collision was +4m/s and -1m/s after the c

Goryan [66]

Answer:

<em>The velocity of the truck is 3.33 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=mv.

If we have a system of bodies, then the total momentum is the sum of the individual momentums:

$P=m_1v_1+m_2v_2+...+m_nv_n$

If some collision occurs, the velocities change to v' and the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

In a system of two masses:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

There are two objects: The m1=4000 Kg car and the m2=6000 Kg truck. The car was moving initially at v1=4 m/s and the truck was at rest v2=0. After the collision, the car moves at v1'=-1 m/s. We need to find the velocity of the truck v2'. Solving for v2':

$\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}$

Substituting:

$\displaystyle v'_2=\frac{4000*4+6000*0-4000(-1)}{6000}$

$\displaystyle v'_2=\frac{16000+4000}{6000}$

$\displaystyle v'_2=3.33$

The velocity of the truck is 3.33 m/s

7 0

3 years ago

Which term below best describes the forces on an object with a a net force of zero?

dybincka [34]

Answer:

B. Balanced Forces

Explanation:

The net force is defined as the sum of all the forces acting on an object. Therefore, if the forces are balanced, they will counteract each other, causing the net force to be zero, then the object will continue at rest or moving with constant velocity.

4 0

4 years ago

What equation can be used to solve for acceleration

Tanya [424]

Answer: acceleration can be calculated when a known force is acting on an object of known mass. Newton’s law can be represented by the equation F net = m x a, where F net is the total force acting on the object, m is the object’s mass, and a is the acceleration of the object.

Explanation:

3 0

3 years ago