Answer:
50m; 0m/s.
Explanation:
Given the following data;
Initial velocity = 20m/s
Acceleration, a = - 4m/s²
Time, t = 5secs
To find the displacement, we would use the second equation of motion;
![S = ut + \frac {1}{2}at^{2}](https://tex.z-dn.net/?f=%20S%20%3D%20ut%20%2B%20%5Cfrac%20%7B1%7D%7B2%7Dat%5E%7B2%7D)
Substituting into the equation, we have;
![S =20*5 + \frac{1}{2}*(-4)*5^{2}](https://tex.z-dn.net/?f=%20S%20%3D20%2A5%20%2B%20%5Cfrac%7B1%7D%7B2%7D%2A%28-4%29%2A5%5E%7B2%7D)
![S =100 + (-2)*25](https://tex.z-dn.net/?f=%20S%20%3D100%20%2B%20%28-2%29%2A25)
![S =100 - 50](https://tex.z-dn.net/?f=%20S%20%3D100%20-%2050)
S = 50m
Next, to find the final velocity, we would use the third equation of motion;
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
<em>Substituting into the equation, we have;</em>
V = 0m/s
<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>
Answer:
Explanation:
Energy stored in a capacitor
= 1/2 C₁V²
capacity of a capacitor
c = εK A / d
k is dielectric and d is distance between plates .
When the distance between the plates is halved and then filled with a dielectric (κ = 4.3)
capacity becomes 4.3 x 2 times
New capacity
C₂ = 8.6 C₁
Energy of modified capacitor
1/2 C₂ V²= 1/2 x 8.6 c x V²
Energy becomes
8.6 times.
Energy stored = 8.6 x 10⁻⁴ J
Answer:
The magnitude of the acceleration of each block is, a = 2.56 m/s²
The tension in the string is, T = 43.05 N
Explanation:
Given data,
The larger block of mass, M = 8.00 kg
The smaller block of mass, m = 3.50 kg
The formula for Atwood machine is,
Ma = Mg - T
ma = T - mg
Adding those equations,
a (M + m) = g ( M - m)
a = (M + m) / ( M - m)
Substituting the values,
a = (8 + 3.5) / (8 - 3.5)
= 2.56 m/s²
The magnitude of the acceleration of each block is, a = 2.56 m/s²
The tension in the string,
T = m(a + g)
= 3.5 ( 2.56 + 9.8)
= 43.05 N
The tension in the string is, T = 43.05 N