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3 years ago

Which statement will be true if you increase the frequency of a periodic wave?

2 answers:

6 0

"The number of waves per second will increase" is the statement among the choices given in the question that <span>will be true if you increase the frequency of a periodic wave. The correct option among all the options that are given in the question is the first option or option "A". I hope that the answer has helped you.</span>

ra1l [238]3 years ago

3 0

"The number of waves per second will increase" is the statement among the choices given in the question that will be true if you increase the frequency of a periodic wave. The correct option among all the options that are given in the question is the first option or option "A". I hope that the answer has helped you.

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Active listening includes all of the following EXCEPT: A. paraphrasing B. clarifying C. ignoring D. empathizing Please select th

scoray [572]

Answer:

C: Ignoring

Explanation:

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8 0

3 years ago

A racecar on a straight track, starting from rest*, steps on the

kirill115 [55]

I think the answer is C

6 0

3 years ago

A brand of earplugs reduces the sound intensity level by 27 dB.By what factor do these earplugs reduce the acoustic intensity?

Fofino [41]

Answer:

Explanation:

27dB = 2.7 B

So I / I₀ = 10⁻²°⁷ , I₀ is intensity of main sound and I is intensity after reduction.

= 1.99 X 10⁻³

So intensity will reduce by 1.99 X 10⁻³ .

3 0

3 years ago

If there is an increase in demand for a product, and that is the only thing that changes, what will that do to the price of the

Eva8 [605]

I believe that the price will rise.
Hope this helps!

5 0

3 years ago

Read 2 more answers

A small airplane takes on 302 l of fuel. If the density of the fuel is 0.821 g/ml, what mass of fuel has the airplane taken on?

ella [17]

To calculate the mass of the fuel, we use the formula

$m = V \times \rho$

Here, m is the mass of fuel, V is the volume of the fuel and its value is $V =302 \ L = 302 \ L \times \frac{10^{3}m L }{L} = 302 \times 10^{3} \ mL$ and $\rho$ is the density and its value of 0.821 g/mL.

Substituting these values in above relation, we get

$m = 302 \times 10^{3} \ mL \times 0.821 g/mL = 247942 g \\\\ m = 247. 94 \ kg$

Thus, the mass of the fuel 247 .94 kg.

8 0

3 years ago