Explanation:
Given that,
A girl pushes her little brother on his sled with a force of 200. N for 850. m
We need to find the work done by the force of friction acting on the sled. The force of friction is 200 N
Net force = 200 N - 200 N = 0
Work done = 0
If force of friction is 300 N.
Net force = 300 N - 200 N = 100 N
The work done by a force is given by :
W = Fd
Put values,
W = 100 × 850
W = 85000 J
Hence, this is the required solution.
Answer:
F= 0.009 N
Explanation:
Given that
Charge ,q= 5.13 μC
Velocity ,V= 8.64 x 10⁶ m/s
Magnetic field , B = 1.99 x 10⁻⁴ T
The force on a charge q moving with velocity v is given as follows
F= q V B
Now by putting the values in the above equation we get
[tex]F= 5.13\times 10^{-6}\times 8.64\times 10^{6}\times 1.99\times 10^{-4}\ N [\tex]
F=0.00882 N
F= 0.009 N
Therefore the force on the particle will be 0.009 N.
This is most likely an example of kinetic energy.
Answer:
K = 4.43 10⁻¹⁸ J
Explanation:
The energy of the atoms on the surface of the sun is ‘
E = K + U
where the potential energy is given by
U = - k q² / r
the total energy is given by the thermal energy
E = k T
let's substitute in the first equation
k T = K - k e² / r
K = kT + k e2 / r
the constant are worth
k the Boltzmann constant k = 1,381 10-23 J / K
k the Coulomb cosntnate k = 8.99 109 N m2 / C2
e the charge of the electron e = 1.6 10-19 C
r the radius of the hydrogen atom r = 0.0529 10-9 m
let's calculate
K = 1.381 10⁻²³ 5500 + 8.99 10⁹ (1.6 10⁻¹⁹)² / 0.0529 10⁻⁹
K = 7.596 10⁻²⁰ + 4.35 10⁻¹⁸
K = 4.43 10⁻¹⁸ J
When sound travels on a certain wave pattern or medium once it hits the surface or surfaces of another wave or mdeium and then it bounces back that is a reflected sound wave.
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