Ask question

Ask question

All categories

3 years ago

10

A balloon is filled with 1500 mL of air at a pressure of 5 atm. What is the pressure of the balloon if the volume is changed to

2500 mL?

1 answer:

Eva8 [605]3 years ago

5 0

Answer:

xcfdbrtbfcgctr dsvrd

Explanation:

ds vfg g cd fg

You might be interested in

State Archimedes' principle.

vampirchik [111]

Answer:

Archimedes' principle states that, when a body is partially or completely immersed in a fluid, it experiences an apparent loss in weight that is equal to the weight of the fluid displaced by the immersed part of the body.

Explanation:

Archimedes' principle allows the buoyancy of an object partially or fully immersed in a fluid to be calculated. The downward force on the object is simply its weight. Thus, the net force on the object is the difference between the magnitudes

of the buoyant force and its weight. If this net force is positive, the object rises; if negative, the object sinks; and if zero, the object is neutrally buoyant - that is, it remains in place without either rising or sinking. In simple words,

8 0

2 years ago

Read 2 more answers

Please please need help on this one

Advocard [28]

I’m guessing it’s the last one, trough

4 0

2 years ago

Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia

sergejj [24]

Answer:

0.176m from the flagpole, westward.

Explanation:

Let the Eastward be the positive direction. So initially runner A is at position -6km, running with velocity of 9km/h while runner B is at position 5km running at a velocity of -8km/h. We can conduct the following equation for their distances over the same time t

$s_A = -6 + 9t$

$s_B = 5 - 8t$

When A an B meets, they are at the same position and at the same time. So

$s_A = s_B$

$-6 +9t = 5 - 8t$

$17t = 5 + 6 = 11$

$t = 11/17 = 0.647 s$

$s_A = -6 + 9*0.647 = -0.176 m$

So where they meet is 0.176m from the flagpole, westward.

5 0

2 years ago

A 3kg ball moving at 8 m/s strikes a 2kg ball at rest,if the collision is elastic,what is the speed of the lighter ball if the h

zloy xaker [14]

Answer:

Speed of lighter ball is 4 m/s.

Explanation:

Applying the principle of conservation of linear momentum,

momentum before collision = momentum after collision.

$m_{1}$ $u_{1}$ + $m_{2}$ $u_{2}$ = $m_{1}$ $v_{1}$ - $m_{2}$ $v_{2}$

$m_{1}$ = 3 kg, $u_{1}$ = 8 m/s, $m_{2}$ = 2 kg, $u_{2}$ = 0 m/s ( since it is at rest), $v_{1}$ = 2 m/s, $v_{2}$ = ?

(3 x 8) + (2 x 0) = (8 x 2) - (2 x $v_{2}$ )

24 + 0 = 16 - 2 $v_{2}$

2 $v_{2}$ = 16 - 24

2 $v_{2}$ = -8

$v_{2}$ = $\frac{-8}{2}$

= -4 m/s

This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.

7 0

2 years ago

What Law and explain why.<br><br> An airplane turns on its jets to accelerate down a runway.

Kaylis [27]

Answer:Newton's 2nd law

Explanation:Newton's 2nd law also states that the rate at which an object changes speed is proportional to the force that is exerted. Engines provide thrust and accelerate a plane forward along the runway. If the engines supply a small force, only a small acceleration will result.

5 0

2 years ago