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kykrilka [37]
1 year ago
15

a guage is connected to tank in which the pressure of the fluid is 305kpa above atmospheric. if the absolute presssure of the fl

uid remains unchanged but the gage is in chamber where the air pressure is reduce to a vaccum of 648mmHg what reading in psi will then be observed
Physics
2 answers:
Serjik [45]1 year ago
7 0

Answer:

Explanation:

Hydrostatic pressure at any height below the water surface is calculated by P=hdg where h is the height below the open water surface, d is the density of water and g is the acceleration due to gravity. So if you want to calculate gauge pressure at height h then use formula P=hdg+P∘ where P∘ is atmospheric pressure

raketka [301]1 year ago
3 0
It had yk be yk me we don’t see the yk up there so
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You are driving in a car for 30 minutes, with the windows down and the radio at a high volume. You turn the car off and leave th
matrenka [14]

Answer:

sensory adaption

Explanation:

Sensory adaption is the phenomenon where the intensity of a stimulus experienced by an organism decreases after a certain amount of exposure to the stimulus. This happens in order for us to pay attention to other stimulus.

When you are driving with the windows down and listening to music you are subjected to a lot of stimuli. Here, most of our attention needs to be on driving. So, our brain drowns all the other unneccessary stimuli like the music.

When you enter the car again where the other stimuli which were present while driving are absent, all your attention is diverted to the music. So, your're ears hurt.

6 0
3 years ago
What are the diferent units that we typically use to measure average speed
Juli2301 [7.4K]
Mph= miles per hour
kph= kilometers per hour
6 0
2 years ago
What beat frequencies are possible with tuning forks of frequencies 255, 258, and 260 hz ?
zavuch27 [327]

Possible beat frequencies with tuning forks of frequencies 255, 258, and 260 Hz are 2, 3 and 5 Hz respectively.

The beat frequency refers to the rate at which the volume is heard to be oscillating from high to low volume. For example, if two complete cycles of high and low volumes are heard every second, the beat frequency is 2 Hz. The beat frequency is always equal to the difference in frequency of the two notes that interfere to produce the beats. So if two sound waves with frequencies of 256 Hz and 254 Hz are played simultaneously, a beat frequency of 2 Hz will be detected. A common physics demonstration involves producing beats using two tuning forks with very similar frequencies. If a tine on one of two identical tuning forks is wrapped with a rubber band, then that tuning forks frequency will be lowered. If both tuning forks are vibrated together, then they produce sounds with slightly different frequencies. These sounds will interfere to produce detectable beats. The human ear is capable of detecting beats with frequencies of 7 Hz and below.

A piano tuner frequently utilizes the phenomenon of beats to tune a piano string. She will pluck the string and tap a tuning fork at the same time. If the two sound sources - the piano string and the tuning fork - produce detectable beats then their frequencies are not identical. She will then adjust the tension of the piano string and repeat the process until the beats can no longer be heard. As the piano string becomes more in tune with the tuning fork, the beat frequency will be reduced and approach 0 Hz. When beats are no longer heard, the piano string is tuned to the tuning fork; that is, they play the same frequency. The process allows a piano tuner to match the strings' frequency to the frequency of a standardized set of tuning forks.

Learn more about  beat frequency here : brainly.com/question/14157895

#SPJ4

7 0
2 years ago
define momentum of a body.state law of co?servation of momentum.prove with the help of third law of motion that total momentum o
xxTIMURxx [149]
The momentum of a body is defined as the product of its mass and velocity....

law of momentum of conservation depends on collision,
for a collision occurring between object 1 and object 2 in an isolated system,the total momentum of the two objects before the Collision is equal to the total momentum of two objects after the Collision.....

4 0
3 years ago
A 2.5 kg , 20-cm-diameter turntable rotates at 150 rpm on frictionless bearings. Two 500 g blocks fall from above, hit the turnt
emmainna [20.7K]

The concepts required to solve this problem are those related to the conservation of the angular momentum and the moment of inertia of the disk. We will begin by calculating the moment of inertia of the disc, then the moment of inertia of the disc after the two two blocks hits and sticks to the edges of the turn table. In the end we will apply the conservation theorem.

The radius is given as,

R = \frac{20cm}{2} = 10cm = 0.1m

When a block falls from above and sticks to the turn table, the moment inertia of the turntable increases.

Since two blocks are stick to the turn table, the total final moment of inertia of the turntable is the sum moment of inertias of individual turntable, and two blocks.

I_1 = \frac{1}{2} MR^2

I_1 = \frac{1}{2} (2.5)(0.1)^2

I_1 = 0.0125kg \cdot m^2

The moment of inertia of each block is

I_0 = mR^2

Total moment of inertia of two block is

I_0' = 2mR^2

The final moment of inertia of the turn table is

I_2 = I_1 +I'0

I_2 = I_1 +2mR^2

I_2 = 0.01kg\cdot m^2 + 2(500*10^{-3}kg)(0.1m)^2

I_2 = 0.0225kg\cdot m^2

From the conservation of the angular momentum, the initial angular momentum of the system is equal to final angular momentum of the system,

Rearrange the equation we have that

I_1\omega_2 = I_2\omega_2

\omega_2 = \frac{I_1\omega_2}{I_2}

\omega_2 = \frac{0.01*150rpm}{0.0225}

\omega_2 = 66.67rpm

The magnitude of the turntable's angular velocity is 66.67rpm

3 0
3 years ago
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