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Reptile [31]
2 years ago
15

Equation for the reaction btn nitric acid and metal X whose valence is 3​

Chemistry
1 answer:
viva [34]2 years ago
3 0
(a) Reaction of nitric acid with non-metal:
C+4HNO
3
​
⟶CO
2
​
+2H
2
​
O+4NO
2
​

S+6HNO
3
​
⟶H
2
​
SO
4
​
+2H
2
​
O+6NO
2
​

(b) Nitric acid showing acidic character:
K
2
​
O+2HNO
3
​
⟶2KNO
3
​
+H
2
​
O
ZnO+2HNO
3
​
⟶Zn(NO
3
​
)
2
​
+H
2
​
O
(c) Nitric acid acting as oxidizing agent
P
4
​
+20HNO
3
​
⟶4H
3
​
PO
4
​
+4H
2
​
O+20NO
2
​

3Zn+8HNO
3
​
⟶3Zn(NO
3
​
)
2
​
+4H
2
​
O+2NO

hope that helps you please mark brainliest
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Complete Question

A sample of aluminum, which has a specific heat capacity of 0.897 JB loc ! is put into a calorimeter (see sketch at right) that contains 200.0 g of water. The aluminum sample starts off at 85.6 °C and the temperature of the water starts off at 16.0 °C. When the temperature of the water stops changing it's 20.1 °C. The pressure remains constant at 1 atm. Calculate the mass of the aluminum sample.

Answer:

M=58g

Explanation:

From the question we are told that:

Heat Capacity H=0.897

Mass of water M=200g

Initial Temperature of Aluminium T_a=85.6

Initial Temperature of Water T_{w1}=16.0

Final Temperature of Water  T_{w2}=16.0

Generally

Heat loss=Heat Gain

Therefore

M*0.897*(85.6-20.1) =200*4.184*(20.1-16)

M=58g

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Explanation:

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Also, it is known that relation between E^{o}_{cell} and K is as follows.

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Substituting the given values into the above formula as follows.

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Answer:

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