The question is incomplete, here is the complete question:
Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid (HCO₂H) and 0.230 mol of sodium formate (NaCO₂H) in water sufficient to yield 1.00 L of solution. The Ka of formic acid is 1.77 × 10⁻⁴
a) 2.099
b) 10.463
c) 3.546
d) 2.307
e) 3.952
<u>Answer:</u> The pH of the solution is 3.546
<u>Explanation:</u>
We are given:
Moles of formic acid = 0.370 moles
Moles of sodium formate = 0.230 moles
Volume of solution = 1 L
To calculate the molarity of solution, we use the equation:
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
![pH=pK_a+\log(\frac{[salt]}{[acid]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%29)
![pH=pK_a+\log(\frac{[HCOONa]}{[HCOOH]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5BHCOONa%5D%7D%7B%5BHCOOH%5D%7D%29)
= negative logarithm of acid dissociation constant of formic acid = 3.75
![[HCOONa]=\frac{0.230}{1}](https://tex.z-dn.net/?f=%5BHCOONa%5D%3D%5Cfrac%7B0.230%7D%7B1%7D)
![[HCOOH]=\frac{0.370}{1}](https://tex.z-dn.net/?f=%5BHCOOH%5D%3D%5Cfrac%7B0.370%7D%7B1%7D)
pH = ?
Putting values in above equation, we get:
Hence, the pH of the solution is 3.546
Answer:
Explanation:
pH + pOH = 14
pH + 10 = 14
pH = 14 - 10 = 4
Therefore pH of the solution is 4 .
Answer:
its orginal charge is none then through the reaction it is reduced because then final charge is -1 meaning is went down 1 so its charge was reduced
Hope this helps! :)
Answer:
The result of the atomic theory was atomic theory proposed that all matter was composed of atoms, also postulated that chemical reactions resulted in the rearrangement of the reacting atoms.
The balanced reaction is as below
3A₂B + 2DC₃→ 6 AC + D₂B₃
The number that must be to the left of AC is 6
Explanation
- According to the law of mass conservation , the number of atoms in reactant side must be equal to number to the number of atoms in product side.
- Therefore the equation above is balance since it obey the law of mass conservation.
- For example there is 6 atoms of A in reactant side and 6 in product side.
