Answer:
strength = 10⁻²/10⁻³ = 10 times more acidic
Explanation:
1. A solution with a pH of 9 has a pOH of
pH + pOH = 14 => pOH = 14 - pH = 14 - 9 = 5
2. Which is more acidic, a solution with a pH of 6 or a pH of 4?
pH of 4 => Higher [H⁺] = 10⁻⁴M vs pH of 6 => [H⁺] = 10⁻⁶M
3. How many times more acidic is a solution with a pH of 2 than a solution with a pH of 3?
soln with pH = 2 => [H⁺] = 10⁻²M
soln with pH = 3 => [H⁺] = 10⁻³M
strength = 10⁻²/10⁻³ = 10 times more acidic
4. What is the hydrogen ion concentration [H + ] in a solution that has a pH of 8?
[H⁺] = 10^-pH = 10⁻⁸M
5. A solution has a pOH of 9.6. What is the pH? (Use the formula.)
pH + pOH = 14 => pH = 14 - 9.6 = 4.4
<u>Answer:</u> The energy of one photon of the given light is ![3.79\times 10^{-19}J](https://tex.z-dn.net/?f=3.79%5Ctimes%2010%5E%7B-19%7DJ)
<u>Explanation:</u>
To calculate the energy of one photon, we use Planck's equation, which is:
![E=\frac{hc}{\lambda}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7Bhc%7D%7B%5Clambda%7D)
where,
= wavelength of light =
(Conversion factor:
)
h = Planck's constant = ![6.625\times 10^{-34}J.s](https://tex.z-dn.net/?f=6.625%5Ctimes%2010%5E%7B-34%7DJ.s)
c = speed of light = ![3\times 10^8m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E8m%2Fs)
Putting values in above equation, we get:
![E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{5.25\times 10^{-7}mm}\\\\E=3.79\times 10^{-19}J](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B6.625%5Ctimes%2010%5E%7B-34%7DJ.s%5Ctimes%203%5Ctimes%2010%5E8m%2Fs%7D%7B5.25%5Ctimes%2010%5E%7B-7%7Dmm%7D%5C%5C%5C%5CE%3D3.79%5Ctimes%2010%5E%7B-19%7DJ)
Hence, the energy of one photon of the given light is ![3.79\times 10^{-19}J](https://tex.z-dn.net/?f=3.79%5Ctimes%2010%5E%7B-19%7DJ)
There are 2 unpaired electrons in sulphur orbital...
the volume will be 0.84mol of Y
2Ag2S + 2H2O—>4Ag+2H2S+O2
The reactants are silver sulphide (Ag2s) and water (H2O)