The pressure of the gas is 1.0 bar.
<em>pV</em> = <em>nRT</em>
<em>T</em> = (0 + 273.15) K = 273.15 K
<em>p</em> = (<em>nRT</em>)/<em>V</em> = (2.0 mol × 0.083 14 bar·L·K⁻¹mol⁻¹ × 273.15 K)/44.8 L = 1.0 bar
Answer:
initial temperature=
Explanation:
Assuming that the given follows the ideal gas nature;
mole of gass will remain same at any emperature:
putting all the value we get:
initial temperature=
Multiply the volume in liters (4.00L) by the concentration of the solution in molar (0.250M) to calculate the number of moles of soluto that you need, then multiply the number of moles by the molar mass of sodium hydroxide (39.99 g/mol) to calculate the mass.
4.00L x 0.250 M x 39.99g / 1L = 39.99g
Basically you need one mol of NaOH (39.99g) dissolved in 4 liters of solution.
Answer would be C) Disposal Procedure
