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2 years ago

11

Whenever there is a change of state, such as solid to liquid or liquid to gas, heat energy can be added without a temperature ch

ange because

1 answer:

egoroff_w [7]2 years ago

3 0

Answer:

The change of state requires energy.

Explanation:

Instead of the energy changing the temperature the heat energy is used by changing its form.

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Given the data calculated in Parts A, B, C, and D, determine the initial rate for a reaction that starts with 0.85 M of reagent

elixir [45]

Answer : The initial rate for a reaction will be $3.8\times 10^{-4}Ms^{-1}$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The chemical equation will be:

$A+B+C\rightarrow P$

Rate law expression for the reaction:

$\text{Rate}=k[A]^a[B]^b[C]^c$

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

$6.1\times 10^{-5}=k(0.2)^a(0.2)^b(0.2)^c$ ....(1)

Expression for rate law for second observation:

$1.8\times 10^{-4}=k(0.2)^a(0.2)^b(0.6)^c$ ....(2)

Expression for rate law for third observation:

$2.4\times 10^{-4}=k(0.4)^a(0.2)^b(0.2)^c$ ....(3)

Expression for rate law for fourth observation:

$2.4\times 10^{-4}=k(0.4)^a(0.4)^b(0.2)^c$ ....(4)

Dividing 1 from 2, we get:

$\frac{1.8\times 10^{-4}}{6.1\times 10^{-5}}=\frac{k(0.2)^a(0.2)^b(0.6)^c}{k(0.2)^a(0.2)^b(0.2)^c}\\\\3=3^c\\c=1$

Dividing 1 from 3, we get:

$\frac{2.4\times 10^{-4}}{6.1\times 10^{-5}}=\frac{k(0.4)^a(0.2)^b(0.2)^c}{k(0.2)^a(0.2)^b(0.2)^c}\\\\4=2^a\\a=2$

Dividing 3 from 4, we get:

$\frac{2.4\times 10^{-4}}{2.4\times 10^{-4}}=\frac{k(0.4)^a(0.4)^b(0.2)^c}{k(0.4)^a(0.2)^b(0.2)^c}\\\\1=2^b\\b=0$

Thus, the rate law becomes:

$\text{Rate}=k[A]^2[B]^0[C]^1$

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

$6.1\times 10^{-5}=k(0.2)^2(0.2)^0(0.2)^1$

$k=7.6\times 10^{-3}M^{-2}s^{-1}$

Now we have to calculate the initial rate for a reaction that starts with 0.85 M of reagent A and 0.70 M of reagents B and C.

$\text{Rate}=k[A]^2[B]^0[C]^1$

$\text{Rate}=(7.6\times 10^{-3})\times (0.85)^2(0.70)^0(0.70)^1$

$\text{Rate}=3.8\times 10^{-3}Ms^{-1}$

Therefore, the initial rate for a reaction will be $3.8\times 10^{-3}Ms^{-1}$

6 0

3 years ago

If a solution contains 3.00 moles of NaCl in 8.00 liters of water, what is the molarity?

ExtremeBDS [4]

Answer:

0.375 M

Explanation:

molarity = number of moles of solute/ number of L solution = 3.00 mol/8.00 L=

= 0.375 mol/L = 0.375 M

8 0

4 years ago

Determine the mass in grams of each element.

jeka57 [31]

1. The mass of 1.33×10²² mole of Sb is 1.62×10²⁴ g

2. The mass of 4.75×10¹⁴ mole of Pt is 9.26×10¹⁶ g

3. The mass of 1.22×10²³ mole of Ag is 1.32×10²⁵ g

4. The mass of 9.85×10²⁴ mole of Cr is 5.12×10²⁶ g

<h3>1. Determination of the mass of 1.33×10²² mole of Sb</h3>

Mole of Sb = 1.33×10²² mole

Molar mass of Sb = 122 g/mol

Mass of Sb =?

Mass = mole × molar mass

Mass of Sb = 1.33×10²² × 122

Mass of Sb = 1.62×10²⁴ g

<h3>2. Determination of the mass of 4.75×10¹⁴ mole of Pt</h3>

Mole of Pt = 4.75×10¹⁴ mole

Molar mass of Pt = 122 g/mol

Mass of Pt =?

Mass = mole × molar mass

Mass of Pt = 4.75×10¹⁴ × 195

Mass of Pt = 9.26×10¹⁶ g

<h3>3. Determination of the mass of 1.22×10²³ mole of Ag</h3>

Mole of Ag = 1.22×10²³ mole

Molar mass of Ag = 108 g/mol

Mass of Ag =?

Mass = mole × molar mass

Mass of Ag = 1.22×10²³ × 108

Mass of Ag = 1.32×10²⁵ g

<h3>4. Determination of the mass of 9.85×10²⁴ mole of Cr</h3>

Mole of Cr = 9.85×10²⁴ mole

Molar mass of Cr = 52 g/mol

Mass of Cr =?

Mass = mole × molar mass

Mass of Cr = 9.85×10²⁴ × 52

Mass of Cr = 5.12×10²⁶ g

Learn more about mole:

brainly.com/question/13314627

7 0

2 years ago

To determine the concentration of SO4 2– ion in a sample of groundwater, 100.0 mL of the sample is titrated with 0.0250 M Ba(NO3

Brrunno [24]

Answer:

1.87x10⁻³ M SO₄²⁻

Explanation:

The reaction of SO₄²⁻ with Ba²⁺ (From Ba(NO₃)₂) is:

SO₄²⁻(aq) + Ba²⁺(aq) → BaSO₄(s)

<em>Where 1 mole of SO₄²⁻ reacts per mole of Ba²⁺</em>

<em />

To reach the end point in this titration, we need to add the same moles of Ba²⁺ that the moles that are of SO₄²⁻.

Thus, to find molarity of SO₄²⁻ we need to find first the moles of Ba²⁺ added (That will be the same of SO₄²⁻). And as the volume of the initial sample was 100mL we can find molarity (As ratio of moles of SO₄²⁻ per liter of solution).

<em>Moles Ba²⁺:</em>

7.48mL = 7.48x10⁻³L ₓ (0.0250moles / L) = 1.87x10⁻⁴ moles of Ba²⁺ = Moles of SO₄²⁻

<em>Molarity SO₄²⁻:</em>

As there are 1.87x10⁻⁴ moles of SO₄²⁻ in 100mL = 0.1L, molarity is:

1.87x10⁻⁴ moles of SO₄²⁻ / 0.1L =

<h3> 1.87x10⁻³ M SO₄²⁻</h3>

8 0

3 years ago

What happens to the rate of dissolution as the temperature is increased in a gas solution?

Nina [5.8K]

Answer:

The rate decreases

Explanation:

When we dissolve a gas in a water, the process is exothermic. This implies that heat is evolved upon dissolution of a gas in water.

Recall from Le Chateliers principle that for exothermic reactions, an increase in temperature favours the reverse reaction. The implication of these is that when the temperature of the gas is increased, less gas will dissolve in water.

Hence increase in temperature decreases the rate of solubility of a gas in water.

8 0

3 years ago