All of the above. If you are going to narrow it down, it would be high voltage and radioactivity.
At all times when a lab is being operated no matter what the circumstances
Answer:
0.718L of 0.81M HCl are required
Explanation:
Based on the reaction:
Cd(s)+2HCI(aq) → H2(g)+CdCl2(aq)
<em>1 mol of Cd reacts with 2 moles of HCl</em>
<em />
To solve this question we must, as first, find the moles of Cd. With the moles of Cd we can find the moles of HCl needed to react completely with the Cd. With the moles and the molarity we can find the volume:
<em>Moles Cd -Molar mass: 112.411g/mol-:</em>
32.71g * (1mol / 112.411g) = 0.2910 moles Cd
<em>Moles HCl:</em>
0.2910 moles Cd * (2 moles HCl / 1mol Cd) =
0.5820 moles HCl
<em>Volume:</em>
0.5820 moles HCl * (1L / 0.81moles) =
<h3>0.718L of 0.81M HCl are required</h3>
Answer: 1820 mL (to 3 sf)
Explanation:
The atomic mass of aluminum is 26.9815385 g/mol, so 4.10 g of aluminum is equal to 4.10/26.9815385 = 0.15195575300497 moles of Al.
From the coefficients of the equation, we know that for every 2 moles of aluminum consumed, 6 moles of HCl are consumed.
So, this means we need 0.15195575300497(6/2) = 0.45586725901491 moles of HCl.
Substituting into the molarity formula,
- 0.250 = 0.45586725901491/(liters of HCl)
- liters of HCl = 0.45586725901491/0.250
- liters of HCl = 1.8234690360596 L = 1820 mL (to 3 sf)
There is a shortcut trick while doing such fill in the blanks of nuclear reactions of hydrogen and helium
Let a,b,care elements of set N
Now
for our question
Hence b=4-3+1=1+1=2
So
The missing place should b e deuterium of heavy water
In nuclear reactions energy is released so it's mentioned on product side not reactant side
