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uranmaximum [27]
3 years ago
11

WHAT IS THISS SOMEONE PLEASE HELP MEEE

Chemistry
1 answer:
Mandarinka [93]3 years ago
5 0
It looks like a bunch of squares. Lolb
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I need so much help 50 points!!!!!! complete the graph
sergij07 [2.7K]
Where is the graph at? may you send a picture of it?
5 0
3 years ago
Which element, under normal circumstances, does not combine chemically with other elements to form compounds?
Ilya [14]
That would be the NOBLE GASES (Helium, Neon, Argon, Krypton, Xenon, Radon).  Because these elements have a filled outer shell (thus giving them the full octet that other elements crave), they are stable elements under normal circumstances and as such resist chemical combination.


Plz note that under special conditions, noble gases such as Xenon and Radon can form compounds  (Xenon Fluoride and Oxide; Radon Fluoride) 
8 0
3 years ago
Read 2 more answers
A sample of gas is inside of a rigid container with fixed volume of 350mL. The initial pressure of the system is 366kPa, and the
Cerrena [4.2K]

Answer:

457.5kPa

Explanation:

Given data

V1=V2=350mL  (<em>fixed volume</em> )

P1=366kPa

T1= 88 degrees Celsius

P2=??

T2= 110 degrees Celsius

For the general gas equation

P1V1/T1= P2V2/T2

V1=V2

P1/T1= P2/T2

Substitute

366/88= P2/110

Cross multiply we have

P2*88=366*110

P2*88= 40260

P2= 40260/88

P2= 457.5 kPa

Hence the pressure will change to 457.5kPa

3 0
3 years ago
A gas has a volume of 420 L at a temperature of -42.0 degrees celsius. What volume will the gas occupy at 18.0 degrees celsius?
Hoochie [10]

Formula

V/T = V1/T1

Givens

V = 430 L

T = - 42 °C = - 42 + 273 = 231°K

V1 = ??

T1 = 18°C + 273 = 291°K

The pressure is a constant.

Solution

420/231 = V1/291         Multiply by 291

420*291 / 231 = V1

V1 = 122220 / 231

V1 = 521.1 L  

6 0
4 years ago
If 1.10 g of steam at 100.0 °C condenses into 38.5 g of water, initially at 27.0 °C, in an insulated container, what is the fina
Gwar [14]

Answer:

Temperature = 44.02°C

Explanation:

Insulated container indicates no heat loss to the surroundings.

The specific heat capacity of a substance is a physical property of matter. It is defined as the amount of heat that is to be supplied to a unit mass of the material to produce a unit change in its temperature.

The SI unit of specific heat is joule per kelvin and kilogram, J/(K kg).

Now,

Specific heat for water is 4.1813 Jg⁻¹K⁻¹.

Latent heat of vaporization of water is 2257 Jg⁻¹.

Energy lost by steam in it's process of conversion to water, is the energy acquired by water resulting in an increase in it's temperature.

Q = mS \Delta T

Q= Heat transferred

m= mass of the substance

T= temperature

Also,

Q = mL

L= Latent heat of fusion/ vaporization ( during phase change)

Now applying the above equations to the problem:

m_{w} S_{w} (T-27) = (m_{s} L) + m_{s}S_{w} (100 -T)

38.5 \times 4.1813 \times (T-27) = (1.10 \times 2257) + 1.10 \times 4.1813 \times (100 -T)

Temperature = 44.02°C

8 0
3 years ago
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