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valentinak56 [21]
2 years ago
7

6. Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast

. His new time compared with the old time was: (a) three times as much, (b) twice as much, (c) the same, (d) half as much, (e) a third as much​
Physics
1 answer:
nata0808 [166]2 years ago
5 0
<h3><em><u>given</u></em><em><u>:</u></em></h3>

<em><u>first</u></em><em><u> </u></em><em><u>trip</u></em><em><u>=</u></em><em><u> </u></em><em><u>5</u></em><em><u>0</u></em><em><u> </u></em><em><u>miles</u></em><em><u>.</u></em>

<em><u>second</u></em><em><u> </u></em><em><u>trip</u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>miles</u></em><em><u>.</u></em>

<h3><em><u>to</u></em><em><u> </u></em><em><u>find</u></em><em><u>:</u></em></h3>

<em><u>his</u></em><em><u> </u></em><em><u>new</u></em><em><u> </u></em><em><u>time</u></em><em><u> </u></em><em><u>compared</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>old</u></em><em><u> </u></em><em><u>time</u></em><em><u>.</u></em>

<h3><em><u>solution</u></em><em><u>:</u></em></h3>

<em><u>Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.</u></em>

<em><u>Speed = Distance/Time</u></em>

<em><u>So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.</u></em>

<em><u>= 100/x hr</u></em>

<em><u>Therefore</u></em><em><u>,</u></em><em><u> </u></em><em><u>his new time compared with the old time was twice as much.</u></em>

<em><u>answer</u></em><em><u>=</u></em><em><u> </u></em><em><u>b</u></em><em><u>)</u></em><em><u> </u></em><em><u>twice</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>much</u></em>

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Question 20 (4 points)
irinina [24]

Explanation:

C is correct.

Newton second law states that force is directly proportional to acceleration with m being the constant of variation.

f _{net} = m(a)

So

250 = 50(a)

a = 5

A is wrong, the constant g only happens in free fall or in vertical direction

B and D are wrong due to the mathematical error or equation error

3 0
2 years ago
David is driving a steady 28.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady
rodikova [14]

Answer:

Explanation:

Let t represent the time for Tina to catch David.

Hence, considering the equation of linear motion S = ut + 1/2at^2..... 1

For David u = 28.0 m/s where 'a' is set to nought

S = ut

S = 28t.......2

For Tina consider equation 1

Where acceleration = 2.90m/s^2 and u is set at nought

S = 1/2×2.90 m/s×t^2.......3

Equate 2 and 3

28t = 1.45t^2

Divide through by t

28 = 1.45t

t = 28/1.45

t = 19.31seconds

Now put the value of t into equation 3

S = 1/2×2.90 m/s×t^2.......3

= 1.45×20×20

= 580m

Tina must have driven 580meters before passing David

Considering the equation of linear motion : V^2 = U^2+2as

Where u is set at nought

V^2 = 2as

V^2 = 2×2.9×580

V^2 = 3364

V = √3364

V = 58m/s

Her speed will be 58m/s

7 0
3 years ago
If you walk at an average speed of 5 km/h for 30 minutes, how
Inessa05 [86]

The distance that would be accumulated during the journey is 2.5 meters

The parameters given in the question are  written below;

average speed= 5 km/hr

time = 30 minutes

convert 30 minutes to hours

= 30/60

= 0.5 hours

Distance-= speed × time

= 5 × 0.5

= 2.5 meters

Hence the distance of the entire journey is 2.5 meters

Please see the link below for more information

brainly.com/question/24268730?referrer=searchResults

3 0
3 years ago
Hitungkan pecutan bagi blok di bawah: / Cal<br>(a)<br>m= 2 kg<br>F= 8.0 N​
ioda

Answer:

Acceleration = 4 m/s²

Explanation:

Given the following data;

Force = 8 N

Mass = 2 kg

To find the acceleration of the block;

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

Acceleration = \frac {Net \; force}{mass}

Substituting into the formula, we have;

Acceleration = \frac {8}{2}

Acceleration = 4 m/s²

4 0
3 years ago
4. A family leaves from New York City and is flying to Los Angles which is 2800mi away. It takes
Blizzard [7]

The average speed of the whole travel is equal to <u>400 mph</u>.

Why?

From the statement, we know that whole travel is divided into three parts. For the first part (traveling from New York to Chicago), we have that it was 3.25 hours and the covered distance was half of the total distance (1400mi). For the second part, we have that it was 1 hour (layover time), and the covered no distance. For the third part (traveling from Chicago to Los Angeles), we have that it was 2.75 hours, and it took the other half of the total distance (1400mi).

We can calculate the average speed of the whol travel using the following formula:

AverageSpeed=\frac{distance_{1}+distance_{2}+distance_{3}}{time_{1}+time{2}+time_{3}}

Now, substituting and calculating, we have:

AverageSpeed=\frac{1400mi+0mi+1400mi}{3.25h+1h+2.75h}

AverageSpeed=\frac{2800mi}{7h}=400mph

Hence, we have the average speed of the whole travel is equal to 400 mph.

Have a nice day!

7 0
4 years ago
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