1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
soldi70 [24.7K]
3 years ago
9

Explain what resonance is and give one example of a destructive outcome of resonance. Also give one example of a non-destructive

outcome of resonance. Use details to support your answer.
Physics
1 answer:
DaniilM [7]3 years ago
3 0

Answer:

resonance is when a body is made to vibrate with the frequency of another body without touching it.

Explanation:

example of destructive: soldiers matching on a bridge unanimously can make the bridge collapse.

You might be interested in
i just said something super cringey to someone and now i wish i had a time machine because i cant forget it :((( SOME HELP PLEAS
Llana [10]

Answer:

what did you say???

Explanation:

6 0
2 years ago
Read 2 more answers
1, 2, & 3.........................
oksian1 [2.3K]

Answer:

1 is correct

2 is -150  

4 0
3 years ago
Define the term work​
bagirrra123 [75]

Answer:

Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force

Explanation:

at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.

5 0
3 years ago
Read 2 more answers
Determine the weight in newtons of a woman whose weight in pounds is 157. Also, find her mass in slugs and in kilograms. Determi
DerKrebs [107]

Answer:

Weight of the woman in Newton

   x =  698.6 \  N

 Mass of the woman in slug

  Mass =  4.86 \  slug

 Mass of the woman in kg

   Mass =  16 \  kg

  My weight in Newton

  W =  784 \  N

Explanation:

From the question we are told that

   The weight of the woman in pounds is  W = 157 \ lb

Converting to Newton

    1 N  =  0.22472 lb

    x N  =  157

=>   x =  \frac{157 *  1}{0.22472}

=>   x =  698.6 \  N

Obtaining the mass in slug

   Mass =  \frac{W}{g}

Here  g =  32.2 ft/s^2

So

     Mass =  \frac{157 }{32.2}

       Mass =  4.86 \  slug

Obtaining the mass in kilogram

     Mass =  \frac{W}{g}

Here  g =  9.8 \  m/s

So

   Mass =  \frac{157 }{9.8}

   Mass =  16 \  kg

Generally weight is mathematically represented as

     W =  m *  g

Given that my mass is   80 kg   then my weight is  

     W =   80 *9.8

      W =  784 \  N

6 0
3 years ago
(a) A load of coal is dropped (straight down) from a bunker into a railroad hopper car of inertia 3.0 × 104 kg coasting at 0.50
Firlakuza [10]

Answer:

a) m=20000Kg

b) v=0.214m/s

Explanation:

We will separate the problem in 3 parts, part A when there were no coals on the car, part B when there is 1 coal on the car and part C when there are 2 coals on the car. Inertia is the mass in this case.

For each part, and since the coals are thrown vertically, the horizontal linear momentum p=mv must be conserved, that is, p=m_Av_A=m_Bv_B=m_Cv_C, were each velocity refers to the one of the car (with the eventual coals on it) for each part, and each mass the mass of the car (with the eventual coals on it) also for each part. We will write the mass of the hopper car as m_h, and the mass of the first and second coals as m_1 and m_2 respectively

We start with the transition between parts A and B, so we have:

m_Av_A=m_Bv_B

Which means

m_hv_A=(m_h+m_1)v_B

And since we want the mass of the first coal thrown (m_1) we do:

m_hv_A=m_hv_B+m_1v_B

m_hv_A-m_hv_B=m_1v_B

m_1=\frac{m_hv_A-m_hv_B}{v_B}=\frac{m_h(v_A-v_B)}{v_B}

Substituting values we obtain

m_1=\frac{(3\times10^4Kg)(0.5m/s-0.3m/s)}{0.3m/s}=20000Kg=2\times10^4Kg

For the transition between parts B and C, we can write:

m_Bv_B=m_Cv_C

Which means

(m_h+m_1)v_B=(m_h+m_1+m_2)v_C

Since we want the new final speed of the car (v_C) we do:

v_C=\frac{(m_h+m_1)v_B}{(m_h+m_1+m_2)}

Substituting values we obtain

v_C=\frac{(3\times10^4Kg+2\times10^4Kg)(0.3m/s)}{(3\times10^4Kg+2\times10^4Kg+2\times10^4Kg)}=0.214m/s

5 0
3 years ago
Other questions:
  • Trace the path of a ray emitted from the tip of the object toward the focal point of the mirror and then the reflected ray that
    6·1 answer
  • In this problem, you will answer several questions that will help you better understand the moment of inertia, its properties, a
    9·1 answer
  • If wheel turning at a constant rate completes 100 revolutions in 10 s its angular speed is:
    14·1 answer
  • Using the standard convention "positive is up", what is the sign of the acceleration of a rock you throw up (a) as it is going u
    10·1 answer
  • Sam is playing football. She kicks the ball with an average force of 75 N.
    13·1 answer
  • Infer whether a circuit breaker should be connected in parallel to the circuit that it is protecting.
    13·1 answer
  • In the equation, y = A sin( wt - kx ), obtain the dimensional formula ' w ' and ' k.​
    11·1 answer
  • As you are cycling to the Q center one spring day, you pass the construction site at Gant and stop to watch a few minutes. A cra
    10·1 answer
  • EASY BRAINLIEST!!URGENT PLEASE HELP.
    11·1 answer
  • Consider the following arrangement with a frictionless/massless pulley. Determine the force F required to move block A if the co
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!