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trapecia [35]
3 years ago
12

Why does the presence of redshift in spectra of galaxies support an understanding of an expanding universe?

Physics
1 answer:
xenn [34]3 years ago
7 0

Explanation:

Doppler's Effect: If a source is moving towards the observer the frequency of the waves emitted by the source will increase( wavelength will decrease). If the source is moving away from the observer the frequency of the waves emitted by the source will decrease( wavelength will increase). The best example of this is the changing frequency of siren of an ambulance as it moves towards us and then away from us.

The same phenomenon can be observed in celestial objects. When the object will move towards us the wavelength will decrease thus the spectrum will be shifted towards the blue part. This is known as blue shift.

If the object moves away from us the wavelength will increase and thus the spectrum will be shifted towards red part. This is know as Red-shift. This is because red has longer wavelength (620 - 750nm) than blue (450-495nm)

Thus if a galaxy shows us red-shifted spectra it means that it is moving away from us. we have observed this phenomenon in various galaxies thus supporting the expanding universe theory.

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A 0.45 kg rock is projected from the edge of the top of a building with an initial velocity of 11.1m/s at an angle of 50 degrees
Misha Larkins [42]

Answer:

bro just go to an easier class

Explanation:

#nerd

4 0
3 years ago
A science class puts a balloon containing 1.25 l of air at 101 kpa into a bell jar. using an air pump, the class removes some of
storchak [24]
The first thing you should know in this case is the following definition:
 PV = nRT
 Then, as the temperature is constant, then:
 PV = k
 Then, we have two states:
 P1V1 = k
 P2V2 = k
 We can then equalize both equations:
 P1V1 = P2V2
 Substituting the values:
 (1.25) * (101) = (2.25) * (P2)
 Clearing P2:
 P2 = ((1.25) * (101)) /(2.25)=56.11Kpa
 answer:
 the new pressure inside the jar is 56.11Kpa
8 0
3 years ago
Can someone please give me the (Answers) to this? ... please ...<br><br> I need help….
IceJOKER [234]

#1.

<em>Car </em>1<em> weighs </em>300 kilograms<em> and is moving right at </em>3 meters per second (m/s)

  • v1 (before) = 3 m/s

  • v2 (before) = -1 m/s

  • v1 (after) = 0.5 m/s

#2.

Law of conservation of momentum

momentum before collorion = momentim after collosion

MV + mv = MV' + mv'

1500x25+ 1000x5

37500 + 15000

6 0
2 years ago
Which of the following would create voltage in a coil of wire?
zubka84 [21]
Its d all the above your welcome
8 0
3 years ago
Your low-flow showerhead is delivering water at 1.2×10−4m3/s, about 2.0 gallons per minute.
Oksanka [162]

To solve this problem it is necessary to apply the fluid mechanics equations related to continuity, for which the proportion of the input flow is equal to the output flow, in other words:

Q_1 = Q_2

We know that the flow rate is equivalent to the velocity of the fluid in its area, that is,

Q = VA

Where

V = Velocity

A = Cross-sectional Area

Our values are given as

Q_2 = 1.2*10^{-4}m^3/s

d = 0.021m

r = \frac{0.021}{2} = 0.0105m

Since there is continuity we have now that,

V_1A_1 = Q_2

V_1A_1 = 1.2*10^{-4}

V_1 = \frac{1.2*10^{-4}}{A_2}

V_1 = \frac{1.2*10^{-4}}{\pi r^2}

V_1 = \frac{1.2*10^{-4}}{\pi (0.0105)^2}

V_1 =0.347m/s

Therefore the speed of the water's house supply line is 0.347m/s

7 0
3 years ago
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