<u>Answer-</u>
<em>The maximum number of watches that Samantha come by with her savings is </em><em>10</em><em>.</em>
<u>Solution-</u>
The amount of money Samantha has in her savings account = $1150
She wants to buy shirts and watches.
Cost of one shirt = $84
Cost of each watch = $99
Let she can buy maximum of x watches, so the net price of the watches is $99x.
Then,

As the number of watches can not be in fraction, so at most she can buy 10 watches.
They're the same. Hopefully this helps.
Answer:
Range: 75 Median: 58 1Q: 40 3Q: 75 Interquartile: 35
Answer:
Step-by-step explanation:
Hello!
So you have a new type of shoe that lasts presumably longer than the ones that are on the market. So your study variable is:
X: "Lifetime of one shoe pair of the new model"
Applying CLT:
X[bar]≈N(μ;σ²/n)
Known values:
n= 30 shoe pairs
x[bar]: 17 months
S= 5.5 months
Since you have to prove whether the new shoes last more or less than the old ones your statistical hypothesis are:
H₀:μ=15
H₁:μ≠15
The significance level for the test is given: α: 0.05
Your critical region will be two-tailed:


So you'll reject the null Hypothesis if your calculated value is ≤-1.96 or if it is ≥1.96
Now you calculate your observed Z-value
Z=<u>x[bar]-μ</u> ⇒ Z=<u> 17-15 </u> = 1.99
σ/√n 5.5/√30
Since this value is greater than the right critical value, i.e. Zobs(1.99)>1.96 you reject the null Hypothesis. So the average durability of the new shoe model is different than 15 months.
I hope you have a SUPER day!