The first law of thermodynamics states the conservation of energy and heat where the total energy in an isolated system may be transformed into another, but never created or destroyed. If 286 J of energy was released to the room, then also 286 J of energy was also removed from food in that refrigerator assuming it is an isolated system. :)
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A :-) it was given the name Newton (N). from this, the derived unit of energy (or work) is defined ,as the work produced when the unit of force causes a displacement equal to the unit of length of its point of application along its direction . It was given the name Joule (J).
Answer:
Answer is Endothermic Reaction
Explanation:
Basically, melting ice is an endothermic reaction because the ice absorbs (heat) energy, which causes a change to occur.
I hope it's helpful!!
According to Newton's second law of motion, Force is the product of mass and acceleration of the object.
So, F = m * a
Here, m = 210 Kg
a = 2.4 * 10⁵ m/s²
Substitute their values,
F = 210 * 2.4 * 10⁵ N
F = 504 * 10⁵ N
F = 5.04 * 10⁷ N
In short, Your Answer would be Option B
Hope this helps!
Answer:
(A) Total energy will be equal to ![0.044\times 10^{-5}J](https://tex.z-dn.net/?f=0.044%5Ctimes%2010%5E%7B-5%7DJ)
(b) Energy density will be equal to ![0.0175J/m^3](https://tex.z-dn.net/?f=0.0175J%2Fm%5E3)
Explanation:
We have given diameter of the plate d = 2 cm = 0.02 m
So area of the plate ![A=\pi r^2=3.14\times 0.02^2=0.001256m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%3D3.14%5Ctimes%200.02%5E2%3D0.001256m%5E2)
Distance between the plates d = 0.50 mm = ![0.50\times 10^{-3}m](https://tex.z-dn.net/?f=0.50%5Ctimes%2010%5E%7B-3%7Dm)
Permitivity of free space ![\epsilon _0=8.85\times 10^{-12}F/m](https://tex.z-dn.net/?f=%5Cepsilon%20_0%3D8.85%5Ctimes%2010%5E%7B-12%7DF%2Fm)
Potential difference V =200 volt
Capacitance between the plate is equal to ![C=\frac{\epsilon _0A}{d}=\frac{8.85\times 10^{-12}\times 0.001256}{0.50\times 10^{-3}}=0.022\times 10^{-9}F](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B%5Cepsilon%20_0A%7D%7Bd%7D%3D%5Cfrac%7B8.85%5Ctimes%2010%5E%7B-12%7D%5Ctimes%200.001256%7D%7B0.50%5Ctimes%2010%5E%7B-3%7D%7D%3D0.022%5Ctimes%2010%5E%7B-9%7DF)
(a) Total energy stored in the capacitor is equal to
![E=\frac{1}{2}CV^2](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B2%7DCV%5E2)
![E=\frac{1}{2}\times 0.022\times 10^{-9}\times 200^2=0.044\times 10^{-5}J](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.022%5Ctimes%2010%5E%7B-9%7D%5Ctimes%20200%5E2%3D0.044%5Ctimes%2010%5E%7B-5%7DJ)
(b) Volume will be equal to
, here A is area and d is distance between plates
![V=0.001256\times 0.02=2.512\times 10^{-5}m^3](https://tex.z-dn.net/?f=V%3D0.001256%5Ctimes%200.02%3D2.512%5Ctimes%2010%5E%7B-5%7Dm%5E3)
So energy density ![=\frac{Energy}{volume}=\frac{0.044\times 10^{-5}}{2.512\times 10^{-5}}=0.0175J/m^3](https://tex.z-dn.net/?f=%3D%5Cfrac%7BEnergy%7D%7Bvolume%7D%3D%5Cfrac%7B0.044%5Ctimes%2010%5E%7B-5%7D%7D%7B2.512%5Ctimes%2010%5E%7B-5%7D%7D%3D0.0175J%2Fm%5E3)