An airplane travels at 300 mi/h south for 2.00 h and then at 250 mi/h north for 750 miles. what is the average speed for the tri
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Answer:
1178 nm
Explanation:
We are given that
Wavelength of light=
We have to find the thickness of spacer if five dark fringes are observed between the edges of the glass.
Suppose that first dark fringe and fifth dark fringe near spacer, then the path length of light is 4 times the wavelength of light.
The light passes through air film is two times then the change in air film thickness from one edge to other is two times the wavelength of light.
Change in air film thickness from one edge to other edge is same as the thickness of spacer.
Therefore, thickness of spacer=
Thickness of spacer=m
Thickness of spacer=1178 nm
Hence, the thickness of spacer=1178 nm
The answer is 41.25 mph.
The average speed (v) can be expressed as:
v = D/T
where
D is total distance: D = d1 + d2 + d3 + d4
T is total time: T = t1 + t2 + t3 + t4
Now let's calculate distances using the formula: d = v * t:
d1 = v1 * t1 = 20.0 * 0.500 = 10 mi
d2 = v2 * t2 = 40.0 * 1.00 = 40 mi
d3 = v3 * t3 = 30.0 * 0.500 = 15 mi
d4 = v4 * t4 = 50.0 * 2.00 = 100 mi
Thus, the average speed is:
The average speed (v) can be expressed as:
v = D/T
where
D is total distance: D = d1 + d2 + d3 + d4
T is total time: T = t1 + t2 + t3 + t4
Now let's calculate distances using the formula: d = v * t:
d1 = v1 * t1 = 20.0 * 0.500 = 10 mi
d2 = v2 * t2 = 40.0 * 1.00 = 40 mi
d3 = v3 * t3 = 30.0 * 0.500 = 15 mi
d4 = v4 * t4 = 50.0 * 2.00 = 100 mi
Thus, the average speed is: