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aleksklad [387]
3 years ago
13

A book is pushed across the table by a student. The student stops pushing on the book and the book slows down and stops. The for

ce stopping the book is a force known as
A) inertia.
B) friction.
C) the applied force.
D) the action-reaction force.
Physics
2 answers:
V125BC [204]3 years ago
6 0
B. Friction. If the book was touching nothing, there would be no force to change its velocity given to it by the initial push. Because the book is sliding across the table, the molecules in the table are "slowing down" the book because they are exerting the force of friction on the book. What happens is that the charges in the book's molecules are attracted to the charges in the table's molecules. The attracting force is in the negative direction, causing the book to experience friction and therefore slow down.
VashaNatasha [74]3 years ago
3 0
A. inertia 

Because it has to do with the motion of something, especially if it changes its pace. In this example, the book's motion, when sliding on the table, decreased because of less force being given off from the student. 
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A solid conducting sphere of radius 2 cm has a charge of 8microCoulomb. A conducting spherical shell of inner radius 4 cm andout
nika2105 [10]

Answer:

C) 7.35*10⁶ N/C radially outward

Explanation:

  • If we apply the Gauss'law, to a spherical gaussian surface with radius r=7 cm, due to the symmetry, the electric field must be normal to the surface, and equal at all points along it.
  • So, we can write the following equation:

       E*A = \frac{Q_{enc} }{\epsilon_{0}} (1)

  • As the electric field must be zero inside the conducting spherical shell, this means that the charge enclosed by a spherical gaussian surface of a radius between 4 and 5 cm, must be zero too.
  • So, the +8 μC charge of  the solid conducting sphere of radius 2cm, must be compensated by an equal and opposite charge on the inner surface of the conducting shell of total charge -4 μC.
  • So, on the outer surface of the shell there must be a charge that be the difference between them:

        Q_{enc} = - 4e-6 C - (-8e-6 C) = + 4 e-6 C

  • Replacing in (1) A = 4*π*ε₀, and Qenc = +4 μC, we can find the value of E, as follows:

      E = \frac{1}{4*\pi*\epsilon_{0} } *\frac{Q_{enc} }{r^{2} } = \frac{9e9 N*m2/C2*4e-6C}{(0.07m)^{2} } = 7.35e6 N/C

  • As the charge that produces this electric field is positive, and the electric field has the same direction as the one taken by a positive test charge under the influence of this field, the direction of the field is radially outward, away from the positive charge.
6 0
3 years ago
In the demolition of an old building, a 1,300 kg wrecking ball hits the building at 1.07 m/s2. Calculate the amount of force at
Y_Kistochka [10]

Answer: F = 1391 N

Explanation:

The information given to you are:

Mass M = 1300 kg

Acceleration a = 1.07 m/s^2

The magnitude of the force striking the building will be

F = ma

Where

F = force

Substitute mass M and acceleration a into the formula

F = 1300 × 1.07

F = 1391 N

Therefore, the wrecking ball strikes the building with a force of 1391 N

3 0
3 years ago
Explain why it is better to jump and land with bent knees rather than straight legs? Use key physics vocabulary.
BigorU [14]

Answer:

Bent knees

Explanation:

Depending the height your jumping from, if you were jumping from a high structure it's best if you jump and land on knees so you dont sprang your ankles from jumping and landing on your straight legs, you could even pull a muscle if you land on straight legs.

3 0
2 years ago
John’s mass is 95.6 kg, and Barbara’s is 55.3 kg. He is standing on the x axis at xJ = +10.9 m, while she is standing on the x a
Anna11 [10]

Answer:Shifted towards Left by distance of 2.243 m

Explanation:

Given

Mass of john m_1=95.6 kg

Mass of barbara m_2=55.3 kg

John is standing at x=10.9 m

Barbara is standing at x=2.50 m

x_{com}=\frac{m_1x_1+m_2x_2}{m_1+m_2}

x_{com}=\frac{95.6\times 10.9+55.3\times 2.5}{95.6+55.3}

x_{com}=\frac{1180.29}{150.9}

x_{com}=7.821 m

Now if they change their Position then

x'_{com}=\frac{95.6\times 2.5+55.3\times 10.9}{95.6+55.3}

x'_{com}=\frac{841.77}{150.9}

x'_{com}=5.578

Thus we can see that center of mass shifted towards left by a distance of 2.243 m because heavier is shifted towards left

8 0
2 years ago
Why does current flow through a circuit?
Ghella [55]

Answer:

Explanation:

cause it do

3 0
3 years ago
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