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Sliva [168]
2 years ago
6

Part D

Chemistry
1 answer:
Basile [38]2 years ago
5 0

The heat lost by copper(ii) sulfate is equal to heat absorbed by water since the total energy in the system remains constant according to the law of conservation of energy.

<h3>How can the number of moles be determined?</h3>

The number of moles of a substance is determined using the formula below:

  • Number of moles = mass/molar mass

Assuming the mass of copper(ii) sulfate used is <em>Mc</em>, number of moles of copper(ii) sulfate used is:

  • Moles of copper(ii) sulfate = <em>Mc</em>/159.60 moles

The heat absorbed by water is calculated using the formula below:

  • Quantity of Heat, H = mass × specific heat capacity × temperature change

mass of water <em>=</em><em> </em> 10 g

Let temperature change be <em>Tc</em>

Heat<em> </em>absorbed<em> </em>by water = 10 × 4.186 × Tc = 41

86Tc

The change in internal energy, ΔU of copper(ii) sulfate, is given as:

  • ΔU = Q − W

where:

Q =  heat absorbed by water

W  =  work done by or on the system

The enthalpy of the reaction is given as:

  • ΔH= energy released or absorbed/moles of copper (ii) sulfate

Therefore, according to the law of conservation of energy, the total energy in the system remains constant.

Learn more about internal energy change at: brainly.com/question/14126477

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After distilling your crude methyl benzoate, you set aside 4.83 grams of the purified ester. You then prepare the grignard reage
Ber [7]

Answer:

95.6 %

Explanation:

For this question, we will have <u>2 reactions</u>, the formation of the <u>grignard reagent</u> and the <u>formation of the alcohol</u>. The first step then is the calculation of the <u>maximum amount</u> of the grignard reagent. For this, we have to convert the grams to moles and check the smallest value. To do this we have to take into account the <u>following conversion ratios</u>:

Molar mass of Mg = 24 g/mol

Molar mass of phenylmagnesium bromide (C_6H_5Br)= 157 g/mol

Density of bromobenzene= 1.5 g/mL

Molar ratio between Mg and  C_6H_5Br= 1:1

2.3~g~Mg\frac{1~mol~Mg}{24~g~Mg}=0.096~mol~Mg

9.45~mL~\frac{1g}{1.5mL}\frac{1~mol~C_6H_5Br}{157~g}=0.0402~mol~C_6H_5Br

The smallest value is the mol of bromobenzene therefore <u>0.0402 mol</u> of phenylmagnesium bromide would be produced.

The next step is repite the same steps for the reaction of <u>formation of the alcohol</u>. Therefore we have to find the moles of methyl benzoate, so:

Molar mass of methyl benzoate: 136.14 g/mol

4.83~g~\frac{1~mol}{136.14~g}=0.35~mol

The we have to <u>divide by the coefficient</u> of each reactive in the balance reaction. So:

\frac{0.35~mol}{1}=0.35

\frac{0.0402~mol}{2}=0.0201

Therefore the <u>limiting reagent</u> would be the phenylmagnesium bromide. Now, the <u>molar ratio</u> between the phenylmagnesium bromide and triphenyl carbinol is <u>2:1</u>, so the amount of alcohol produced is 0.0201 mol triphenyl carbinol. The next step is the conversion from mol to <u>grams of triphenyl carbinol</u>:

Molar mass of triphenyl carbinol= 260.33 g/mol

0.0201~mol\frac{260.33~g}{1~mol}=5.23~g~triphenyl carbinol

Finally, we have to <u>divide</u> the obtanied solid by the calculated one:

Percentage=\frac{5}{5.23}*100=95.6\%

5 0
3 years ago
ANSWER THIS QUESTION AND GET 10 POINTS AND BRAINLEST
Gelneren [198K]

Answer:

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Explanation:

4 0
3 years ago
Please help me ASAP
blondinia [14]

Answer:

weak acid

Explanation:

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4 0
3 years ago
A solution with a ph of 4 has _________ the concentration of h+ present compared to a solution with a ph of 5.
Marina CMI [18]
<span>A solution with a pH of 4 has ten times the concentration of H</span>⁺<span> present compared to a solution with a pH of 5.
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</span>[H⁺] = 10∧-pH.
pH = 4 → [H⁺]₁ = 10⁻⁴ M = 0,0001 M.
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[H⁺]₁ / [H⁺]₂ = 0,0001 M / 0,00001 M.
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