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Sliva [168]
1 year ago
6

Part D

Chemistry
1 answer:
Basile [38]1 year ago
5 0

The heat lost by copper(ii) sulfate is equal to heat absorbed by water since the total energy in the system remains constant according to the law of conservation of energy.

<h3>How can the number of moles be determined?</h3>

The number of moles of a substance is determined using the formula below:

  • Number of moles = mass/molar mass

Assuming the mass of copper(ii) sulfate used is <em>Mc</em>, number of moles of copper(ii) sulfate used is:

  • Moles of copper(ii) sulfate = <em>Mc</em>/159.60 moles

The heat absorbed by water is calculated using the formula below:

  • Quantity of Heat, H = mass × specific heat capacity × temperature change

mass of water <em>=</em><em> </em> 10 g

Let temperature change be <em>Tc</em>

Heat<em> </em>absorbed<em> </em>by water = 10 × 4.186 × Tc = 41

86Tc

The change in internal energy, ΔU of copper(ii) sulfate, is given as:

  • ΔU = Q − W

where:

Q =  heat absorbed by water

W  =  work done by or on the system

The enthalpy of the reaction is given as:

  • ΔH= energy released or absorbed/moles of copper (ii) sulfate

Therefore, according to the law of conservation of energy, the total energy in the system remains constant.

Learn more about internal energy change at: brainly.com/question/14126477

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Which intermolecular force would affect melting point the most?
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Hydrogen bonding

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How many kilocalories are required to increase the temperature of 15.6 g of iron from 122 °c to 355 °c. the specific heat of iro
Dmitriy789 [7]

Heat require to boil 15.6 g iron from 122 C0to 355 C0 whereas,

Q = m s dT

Where, m is mass of iron

s is specific heat of iron

d T is change in temperature in celcius

= 15.6 g * 0.45 J /g /C * (355 - 122)  = 1.63 * 10^3 J

If  

1 cal = 4.2 J

Then,  

Q = (1.63 * 10^3) /4.2 = 0.389 K cal

Thus 0.389 k cal of enrgy  is required by a 15.6 g Fe to reach to 355 C^0

4 0
3 years ago
A gas at 127०C and 10.0 L expands to 20.0 L. What is the new temperature in Celcius? (HINT: You need to convert to Kelvins solve
Snowcat [4.5K]

Answer:

526.85K

Explanation:

Based on Charles's law, the volume of a gas is directly proportional to absolute temperature. The formrula is:

V₁ / T₁ = V₂ / T₂

<em>Where 1 represents the initial state and 2 the final state of the gas</em>

Using the values of the problem:

V₁ = 10.0L

T₁ = 127°C + 273.15K = 400.15K

V₂ = 20.0L

Thus, replacing in the formula:

10.0L / 400.15K = 20.0L / T₂

T₂ = 800K

In Celsius:

800K - 273.15 =<em> 526.85K</em>

<em />

3 0
3 years ago
How many grams of liquid CF2Cl2 are needed to cool 156 g of water from 42.9 to 20.5 °C? The specific heat of water is 4.184 J/(g
SashulF [63]

To cool 156 g of water from 42.9 °C to 20.5 °C, 101 g of CF₂Cl₂ are required.

CF₂Cl₂ is a refrigerant. When it is evaporated, it absorbs heat from water, which cools.

<h3>What is evaporation?</h3>

Evaporation is a type of vaporization that occurs on the surface of a liquid as it changes into the gas phase.

  • Step 1: Calculate the heat released by water.

We will use the following expression.

Qw = c × m × ΔT = (4.184 J/g.°C) × 156 g × (20.5 °C - 42.9 °C)

Qw = -14.6 kJ

where,

  • Qw is the heat released by water.
  • c is the specific heat of water.
  • m is the mass of water.
  • ΔT is the change in the temperature of water.

If water releases 14.6 kJ of heat, CF₂Cl₂ absorbs 14.6 kJ of heat (Qr = 14.6 kJ).

  • Step 2: Calculate the mass of the refrigerant required.

We will use the following expression.

Qr = ΔH°evap × m

m = Qr/ΔH°evap = 14.6 kJ / (0.144 kJ/g) = 101 g

where,

  • Qr is the heat absorbed by the refrigerant.
  • ΔH°evap is the heat of vaporization of the refrigerant.
  • m is the mass of the refrigerant.

To cool 156 g of water from 42.9 °C to 20.5 °C, 101 g of CF₂Cl₂ are required.

Learn more about evaporation here: brainly.com/question/25310095

4 0
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