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SashulF [63]
3 years ago
10

A small plane is 20 miles due north of the airport. a jet at the same altitude as the plane is 64.5 miles west of the airport. t

o the nearest tenth, what is the distance between the small plane and the jet? enter your answer as a decimal in the box.
Mathematics
1 answer:
podryga [215]3 years ago
3 0

okay realize that the distance traveled by the small plane, distance traveled by jet, and the distance between them makes a right triangle. Using Pythagorean theorem and allowing x be the distance between them, x² = (20 miles)² + (64.5 miles
 x = 67.53 miles the distance between the two entities in nearest tenth is approximately 67.5 miles. 

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Harman [31]

Answer:

we get \mathbf{gf(2)=-\frac{1}{3}}

Step-by-step explanation:

We are given:

f(x)=1-2x\\g(x)= \frac{1}{x}\\h(x)=x^3+1

We need to find value of gf(2)

gf(2)=g(f(2))

First putting f(x) inside of g(x) and then putting x=2

gf(x)=g(f(x))\\gf(x)=\frac{1}{1-2x}

Now putting x=2 to find gf(2)

gf(x)=\frac{1}{1-2x}\\gf(2)=\frac{1}{1-2(2)}\\gf(2)=\frac{1}{1-4}\\gf(2)=\frac{1}{-3}\\gf(2)=-\frac{1}{3}

So, we get \mathbf{gf(2)=-\frac{1}{3}}

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