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Marta_Voda [28]
2 years ago
14

Kellie has built her savings account to $7,800. She is transferring it to an account that earns 5.5% interest, compounded monthl

y. What will the balance of the account be in 16 years?
Mathematics
1 answer:
Pavel [41]2 years ago
7 0

Answer:

Kellie has built her savings account to $7,800. She is transferring it to an account that earns 5.5% interest, compounded monthly. What will the balance of the account be in 16 years?

Step-by-step explanation:

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Which pair of numbers is relatively prime?
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Answer:

B

Step-by-step explanation:

Two numbers are relatively prime when there is no integer greater than one that that is a factor of both of them.

A: 15 and 21 both have a factor of 3.

<u>B</u>: 24 and 49 have no common factors, and therefore, are relatively prime.

C. 35 and 135 both have a factor of 5.

D:  45 and 102 both have a factor of 3.

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The tree frog population in your back yard doubles every two weeks. Currently, there are 10 frogs in your back yard. Assuning th
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Step-by-step explanation:

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Answer:

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3 years ago
two classmates have decided to read all the volumes in a popular series of books. Katie has already read 4 volumes and will cont
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To solve this we can make it into an equation, which looks like this

y = 2x (for Rebecca)
y = x + 10 (for Alice)

The we subtract one equation from the other to solve

0 = x - 10
10 = x
x = 10

Now we replace x in whichever equation and we get 20

So, each girl will read 20 books for them to be at the same book.

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3 years ago
An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the
julia-pushkina [17]

Answer:

The rate of decrease is: 43.2mm^3/min

Step-by-step explanation:

Given

l = 18mm

\frac{dl}{dt} = -0.8mm/min ---- We used minus because the rate is decreasing

Required

Rate of decrease when: l = 18mm

The volume of the cube is:

V = l^3

Differentiate

\frac{dV}{dl} = 3l^2

Make dV the subject

dV = 3l^2 \cdot dl

Divide both sides by dt

\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}

Given that: l = 18mm and \frac{dl}{dt} = -0.8mm/min

\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)

\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min

\frac{dV}{dt} = -43.2mm^3/min

<em>Hence, the rate of decrease is: 43.2mm^3/min</em>

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