Answer:
it's the distance between objects in space
Explanation: Light travels super fast; but it still takes a long time to travel between objects in space. This is because distances between objects in space are enormous.
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Answer: a) vcar= 7 m/s ; b) a train= 0.65 m/s^2
Explanation: By using the kinematic equation for the car and the train we can determine the above values of the car velocity and the acceletarion of the train, respectively.
We have for the car
distance = v car* t, considering the length of train (81.1 m) travel by the car during the first 11.6 s
the v car = distance/time= 81.1 m/11.6s= 7 m/s
In order to calculate the acceleration we have to use the kinematic equation for the train from the rest
distance train = (a* t^2)/2
distance train : distance travel by the car at constant speed
so distance train= (vcar*36.35)m=421 m
the a traiin= (2* 421 m)/(36s)^2=0.65 m/s^2
A change in position with respect to a reference point is called motion
hope it helps...
Answer:
Explanation:
radius of hoop and the radius of disk is same = R
Let the mass of hoop is M and the mass of disk is M'.
As they reach the bottom of teh surface in same time so they travel equal distance thus, they have same acceleration.
The acceleration is given by
As the acceleration is same so that the moment of inertia is also same.
Moment of inertia of disk = moment of inertia of hoop
1/2 x mass of disk x R² = mass of hoop x R²
So, mass of disk = 2 x mass of hoop
Option (c) is correct.
Answer:
0.800 m/s²
Explanation:
First, calculate the angular acceleration:
ω = αt + ω₀
6.00 rad/s = α (3.00 s) + 0 rad/s
α = 2.00 rad/s²
Now calculate the angular velocity at t = 2.00 s:
ω = αt + ω₀
ω = (2.00 rad/s²) (2.00 s) + 0 rad/s
ω = 4.00 rad/s
Calculate the linear velocity:
v = ωr
v = (4.00 rad/s) (0.0500 m)
v = 0.200 m/s
Finally, calculate the centripetal acceleration:
a = v² / r
a = (0.200 m/s)² / (0.0500 m)
a = 0.800 m/s²
