Answer:
so initial momentum is 0.22kgm/s
Explanation:
m1=0.20kg
m2=0.30kg
initial velocity of m1=u1=0.50m/s
initial velocity of m2=u2=0.40m/s
total momentum of the system before collision
Pi=m1u1+m2u2
Pi=0.20kg×0.50m/s+0.30kg×0.40m/s
Pi=0.1kgm/s+0.12kgm/s
Pi=0.22kgm/s
Answer:
Explanation:
From the question we are told that:
Velocity 
Time 
Distance 
Generally the Newton's equation for Speed going down the stream is mathematically given by
Therefore
There simple rules for series and parallel circuits.
For the series circuits we have the following rules:
1)The same current flows through each part of a series circuit.(<span>I = I1 = I2 = I3)
2)</span>The total resistance of a series circuit is equal to the sum of individual resistances.(<span>Req = R1 + R2 + R3)
3)The</span> voltage applied to a series circuit is equal to the sum of the individual voltage drops.(<span>V = V1 + V2 + V3)
</span>For the parallel circuits we have the following rules:
1)Voltage is the same across each component of the parallel circuit.(<span>: V = V1 = V2 = V3)
</span>2)The sum of the currents through each path is equal to the total current that flows from the source.(<span> I = I1 + I2 + I3)
3)The total resistance is equal to the sum of the reciprocal value of individual resistors in the circuit.
The x region represents the series circuit. The y region represents a combination of series and parallel circuit. This means that for y region we can apply laws for both series and parallel circuits.
So, all the equation can be applied to the y region.
However, not all equation can be applied to the x region. We can apply following equation to the x region:
1)</span><span>I = I1 = I2 = I3
</span>2)<span> V = V1 + V2 + V3
3)</span><span>Req = R1 + R2 + R3</span>
I don't know the name, but the opposite of gravity, if that helps!
Answer:
Δy=0.431m
Explanation:
Diffraction grating with split space d,to find the fringe position ym,we must to find the angle from
dSinα=mλ
A grating with N slits or lines per mm has slit spacing of
d=1/N
d=(1/600mm)
d=1.67×10⁻³mm
For 400nm wavelength:
α=Sin⁻¹(mλ/d)
And the position of first order lowest wavelength fringe on the screen is:
For 700nm wavelength:
α=Sin⁻¹(mλ/d)
And the position of first order highest wavelength fringe on the screen is:
The difference between the first order lowest and highest wavelength fringe is
Δy=(0.925595 - 0.49445)m
Δy=0.431m
