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valentina_108 [34]
3 years ago
7

Older railroad tracks in the U.S. are made of 12-m-long pieces of steel. When the tracks are laid, gaps are left between section

s to prevent buckling when the steel termally expands. If a track is laid at 16*C, how large should the gaps be if the track is not to buckle when the temperature is as high as 50*C?
Physics
2 answers:
never [62]3 years ago
8 0

Answer: gap required in track =

5.39millimeter{5.39mm}

Explanation: This is a linear expansivity problem.

Coefficient of Linear expansivity = {gap in lenght}/{{original lenght*.

{change in temperature}}

But coefficient of linear expansivity of steel = 13.2*EXP{-6}/degree Celsius.

Making change in lenght or gap subject of formula we have,

Gap = coefficient of linear expansivity*{{original lenght*{change in temperature}}

But,

Original lenght = 12m

Change in temperature = 50 - 16 = 34 degree Celsius.

Therefore,

Gap in lenght = 13.2*EXP{-6}*12*34=

=5.39*EXP{-3}meter

= 5.39mm

____ [38]3 years ago
6 0

Answer: ∆L = 0.49cm ≈ 0.50cm

Therefore there should be 0.5 cm gap between each piece of steel.

Explanation:

Thermal expansion of steel is the increase in size of steel as a result of increased temperature. It can be represented by the mathematical expression:

∆L = L(k)∆T .....1

Where;

∆L is the change in length

L is the initial length

∆T is the change in temperature

k is the specific Linear expansion coefficient.

Given;

L = 12m

∆T = 50°C - 16°C = 34°C

k (for steel) = 1.2 × 10^-6 /C

Substituting the values into the equation 1

∆L = 12 × 34 × 12×10^-6

∆L = 4896 × 10^-6 m

∆L = 0.49cm ≈ 0.50cm

Therefore there should be 0.5 cm gap between each piece of steel.

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A water bath in a physical chemistry lab is 1.55 m long, 0.710 m wide, and 0.570 m deep (high). If it is filled to within 3.55 i
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Answer:

528 liter.

Explanation:

Volume of the tank(cuboid) = l*b*h

But volume of the water = l*b*h

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b = width of the tank

h = the length from the bottom of the tank,

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Length of the water in the tank = 0.570 - 0.09017

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The stopcock connecting a 2.14 L bulb containing oxygen gas at a pressure of 8.19 atm, and a 9.84 L bulb containing krypton gas
marshall27 [118]

Answer : The final pressure of the system in atm is, 3.64 atm

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1+P_2V_2=P_fV_f

where,

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P_f = final pressure = ?

V_f = final volume = 2.14 L  + 9.84 L = 11.98 L

Now put all the given values in the above equation, we get:

8.19atm\times 2.14L+2.65atm\times 9.84L=P_f\times 11.98L

P_f=3.64atm

Therefore, the final pressure of the system in atm is, 3.64 atm

4 0
3 years ago
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