The lowest note on a piano

Physics

1 answer:

Vadim26 [7]2 years ago

7 0

Answer:

My teacher said 36m when I asked her

Explanation:

HOPE THIS HELPS!!

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You can describe the _______________ of an object by saying it is moving in a straight line or is curved around another object.

velikii [3]

Answer:

You can describe the motion of an object by saying it is moving in a straight line or is curved around another object. You can also describe where an object is by its position in relation to another object. The second object acts as a reference point. When an object changes position, you know it has motion. Motion can also be described by finding an object's speed or how fast or slow it moves in a certain amount of time. In addition, you can describe the object's speed AND direction together. This is called velocity

Explanation:

In the given answer-

Motion is defined as - the change in the movement or position of any object or body.

Position is said to be a place or somewhere or a location where any object or body is particularly placed/located or put on.

Reference point is a fixed point with regards to which any object or body changes its position. It is also called reference origin.

Speed is defined as the rate of any object covering certain distances. It is a scaler quantity (quantity which depends upon only magnitude).

Velocity is defined as the rate of speed per unit time. It is a vector quantity (quantity depending upon both magnitude and direction ).

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2 years ago

if you were floating in the solar system at equal distances between mars (small mass) and jupiter (large mass) which planet woul

tester [92]

You would gravitate towards Jupiter because if it’s large mass it has a stronger gravitational pull

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2 years ago

two cars are moving at constant speeds in a straight line along a major highway. The first is travelling at 20ms^-1 and the seco

Reika [66]

Answer:

$t=750s$

Explanation:

The two cars are under an uniform linear motion. So, the distance traveled by them is given by:

$\Delta x=vt\\x_f-x_0=vt\\x_f=x_0+vt$

$x_f$ is the same for both cars when the second one catches up with the first. If we take as reference point the initial position of the second car, we have: