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bulgar [2K]
3 years ago
14

How many grams of solute are in 1.00 liter of 0.200m na2so4 solution?

Chemistry
1 answer:
Kisachek [45]3 years ago
7 0
Molarity can be defined as the number of moles of solute in 1 L solution.
Molarity of Na₂SO₄ solution - 0.200 M
this means there are 0.200 moles in 1 L solution 
Molar mass of Na₂SO₄ - 142 g/mol 
therefore mass of Na₂SO₄ in 1.00 L - 0.200 mol x 142 g/mol = 28.4 g
a mass of 28.4 g of Na₂SO₄ is present in 1.00 L
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Answer:

1.001

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A gas exerts a pressure of 1.8 atm at a temperature of 60 degrees celsius. What is the new temperature when the pressure of the
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The answer for the following problem is mentioned below.

  • <u><em>Therefore the final temperature of the gas is 740 K</em></u>

Explanation:

Given:

Initial pressure of the gas (P_{1}) = 1.8 atm

Final pressure of the gas (P_{2})  = 4 atm

Initial temperature of the gas (T_{1}) = 60°C = 60 + 273 = 333 K

To solve:

Final temperature of the gas (T_{2})

We know;

From the ideal gas equation;

we know;

P  × V = n × R × T

So;

we can tell from the above equation;

 <u>   P ∝ T</u>

(i.e.)

      <em> </em>\frac{P}{T}<em> = constant</em>

        \frac{P_{1} }{P_{2} } = \frac{T_{1} }{T_{2} }

Where;

P_{1}  = initial pressure of a gas

P_{2} = final pressure of a gas

T_{1} = initial temperature of a gas

T_{2} = final temperature of a gas

        \frac{1.8}{4} = \frac{333}{T_{2} }

   T_{2} =\frac{333*4}{1.8}

    T_{2} = 740 K

<u><em>Therefore the final temperature of the gas is 740 K</em></u>

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A gaseous mixture contains 443.0 Torr H 2 ( g ) , 369.9 Torr N 2 ( g ) , and 82.7 Torr Ar ( g ) . Calculate the mole fraction, χ
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Answer:

χH₂ = 0.4946

χN₂ = 0.4130

χAr = 0.0923

Explanation:

The total pressure of the mixture (P) is:

P = pH₂ + pN₂ + pAr

P = 443.0 Torr + 369.9 Torr + 82.7 Torr

P = 895.6 Torr

We can find the mole fraction of each gas (χ) using the following expression.

χi = pi / P

χH₂ = pH₂ / P = 443.0 Torr/895.6 Torr = 0.4946

χN₂ = pN₂ / P = 369.9 Torr/895.6 Torr = 0.4130

χAr = pAr / P = 82.7 Torr/895.6 Torr = 0.0923

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