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bulgar [2K]
3 years ago
14

How many grams of solute are in 1.00 liter of 0.200m na2so4 solution?

Chemistry
1 answer:
Kisachek [45]3 years ago
7 0
Molarity can be defined as the number of moles of solute in 1 L solution.
Molarity of Na₂SO₄ solution - 0.200 M
this means there are 0.200 moles in 1 L solution 
Molar mass of Na₂SO₄ - 142 g/mol 
therefore mass of Na₂SO₄ in 1.00 L - 0.200 mol x 142 g/mol = 28.4 g
a mass of 28.4 g of Na₂SO₄ is present in 1.00 L
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In this problem, we need to use the ideal gas law. The following is the formula used in ideal gas law: PV = nRT, where n refers to the moles and R is the gas constant.

Given 
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Solution
To get the moles which represent the "n" in the formula, we need to rearrange the equation.

PV = nRT                      PV
----    ------    --->    n = --------
 RT     RT                       RT

          10130.0 kPa  x 50 L
n= ---------------------------------------------
       8.314 L. kPa/K.mol  x 573.15 K
             506,500 
  =  ----------------------------
         4,765.17  mol K

=106.29 mol Ar

So the moles of argon gas is 106.29 moles 
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