<h3>
Answer:</h3>
52 g water
<h3>
Explanation:</h3>
In this question we are given;
Amount of heat, Q = 520 calories
Change in temperature, K = 10 K
We are required to calculate the mass of water.
Amount of heat is calculated by multiplying mass by specific heat capacity by change in temperature.
Q = m × c × Δt
The specific heat capacity,c of water = 1 Cal/g°C or 4.184 J/g°C
Rearranging the formula;
m = Q ÷ cΔt
= 520 Cal ÷ (1 Cal/g°C×10 K)
= 52 g
Thus, the mass of water sample is 52 g
Density
=mass÷volume
=277÷38
=7.29 g/cm3
Answer:
27.25°C
Explanation:
hello,
this question involves heat transfer in an object and to find the final temperature, we'll use formula for heat transfer
data;
mass = 12g
heat energy (Q) = 12J
initial temperature (T1) = 25°C
final temperature (T2) = x
specific heat capacity (c) = 0.444J/g°C
heat energy(Q) = mcΔt
Q = mc(T2 - T1)
the final temperature was 27.25°C
Answer:
The solution that is least concentrated is the one containing 4 moles of solute dissolved in 6 liters of solution .
Explanation:
Concentration is defined as the amount of a substance in a given apquantitybof solvent or solution. The unit of concentration is usually given as mol/litre
Mathematically, concentration = Number of moles of solute/ volume of solution in litres.
To determine the solution that is least concentrated from the given solutions, their concentrations in mol/L is calculated.
Concentration of solution containing 4 moles of solute dissolved in 6 liters of solution = 4 mol/6 litres = 0.67 mol/L
Concentration of solution containing 1 mole of solute dissolved in 1 litre of solution = 1 mol/ 1 litre = 1 mol/L
Concentration of solution containing 1 mole of solute dissolved in 1 liter of solution = 1 mol/ 1 litre = 1 mol/L
Concentration of solution containing 8 moles of solute dissolved in 4 liters of solution = 8 moles / 4 litres = 2 mol/L
Concentration of solution containing 8 moles of solute dissolved in 4 liters of solution = 8 moles/ 4 litres = 2 mol/L
Concentration of solution containing 3 moles of solute dissolved in 2 liters of solution = 3 moles / 2 litres = 1.5 mol/L
Therefore, the solution that is least concentrated is the one containing 4 moles of solute dissolved in 6 liters of solution .
