Explanation:
The given balanced reaction is as follows.
It is given that mass of ammonium nitrate is 86.0 kg.
As 1 kg = 1000 g. So, 86.0 kg = 86000 g.
Hence, moles of present will be as follows.
Moles of =
=
= 1074.42 mol
Therefore, moles of ,
and
produced by 1074.42 mole of
will be as follows.
Moles of =
= 537.21 mol
Moles of =
= 1074.42 mol
Moles of =
= 2148.84 mol
Therefore, total number of moles will be as follows.
537.21 mol + 1074.42 mol + 2148.84 mol
= 3760.47 mol
According to ideal gas equation, PV = nRT. Hence, calculate the volume as follows.
PV = nRT
1 atm \times V = 3760.47 mol \times 0.0821 L atm/mol K \times 580 K[/tex] (as = 307 + 273 = 580 K)
V = 179066.06 L
Thus, we can conclude that total volume of the gas is 179066.06 L.