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2 years ago

How many moles of oxygen are in 5.6 moles of al(oh)3?

Chemistry

1 answer:

Mashcka [7]2 years ago

7 0

5.6 Al(OH)3
5.6 Al, 16.8 O, 16.8 H

16.8 mols of oxegyn in 5.6 mols of Al(OH)3

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PLEASE HELP!!!

WINSTONCH [101]

The net ionic equation of the reaction is:

Pb²⁺aq) + 2 I(aq) → PbI2(s)

<h3>What is a net ionic ionic equation?</h3>

A net ionic equation is an equation which shows only the ions that are involved in the formation of a product in the reaction as well as the product of the reaction alone. Spectator ions are omitted.

The net ionic equation of the reaction is given below:

Pb²⁺aq) + 2 I(aq) → PbI2(s)

In conclusion, a net ionic equation does not show spectator ions.

Learn more about net ionic equation at: brainly.com/question/19705645

#SPJ1

6 0

1 year ago

A compressed gas cylinder is filled with 5270 g of argon gas. The pressure inside the cylinder is 2050 psi at a temperature of 1

LuckyWell [14K]

Answer:

A compressed gas cylinder is filled with 5270 g of argon gas.

The pressure inside the cylinder is 2050 psi at a temperature of 18C.

The valve to the cylinder is opened and gas escapes until the pressure inside the cylinder is 650. psi and the temperature are 26 C.

How many grams of argon remains in the cylinder?

Explanation:

First, calculate the volume of argon gas that is present in the gas cylinder by using the ideal gas equation:

Mass of Ar gas is --- 5270g.

The number of moles of Ar gas:

$Number of moles of Ar gas=\frac{given mass of Ar}{its atomic mass} \\ =\frac{5270g}{39.948g/mol} \\ =131.9mol$

Temperature T=(18+273)K=291K

Pressure P=2050psi

$2050* 0.0680atm\\\\=139.4atm\\$

Volume V=?

$PV=nRT\\139.4atm * V=131.9mol *0.0821L.atm.mol-1.K-1 * 291K\\=>V=\frac{131.9mol *0.0821L.atm.mol-1.K-1 * 291K}{139.4atm} \\=>V=22.6L$

Using this volume V=22.6L

Pressure=650psi=44.2atm

Temperature T= (26+273)K=299K

calculate number of moles "n" value:

$PV=nRT\\=>n=\frac{PV}{RT} \\=>n=\frac{44.2atm*22.6L}{0.0821L.atm.mol^-1K^-1* 299K} \\=>n=40.7mol$

Mass of 40.7mol of Ar gas:

$mass of Ar gas=number of moles * its atomic mass\\\\ =40.7mol* 39.948g/mol\\\\ =1625.8g$

Answer:

The mass of Ar gas becomes 1625.8g.

8 0

2 years ago

I have this chemistry question and I’m really struggling to answer it. Can someone please help me figure out the steps & the

Digiron [165]

Answer: 133,333.333 meters.

Explanation:

I forgot how to explain this looool.

7 0

2 years ago

The reaction of 5.40 g of carbon with excess O2 yields 13.6 g of CO2. What is the percent yield of this reaction?

vazorg [7]

C + O2= CO2
$n = \frac{m}{mw}$
$n = \frac{5.4}{12} \\ n = 0.45 \: mol \: of \: carbon$
$n = \frac{13.6}{12 + 16 \times 2} \\ n = \frac{13.6}{44} \\ n = 0.31 \: mol \: of \: carbon \: dioxide$
CO2 is limit
5.4-3.72= 1.68 g of C is excess
5.4 g = 100%
3.72 g = x
x=68.9 %

4 0

2 years ago

What two measurements are needed to calculate speed?

Alchen [17]

Answer:

Two essential measurements to calculating average speed are Distance and Time

Explanation:

hope it helps you

5 0

2 years ago

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