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2 years ago

6

What is the solvent for a solution made by dissolving sodium chloride into water?

1 answer:

Aleksandr [31]2 years ago

5 0

it is water because it is dissolving the sodium chloride

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How would increased chlorofluorocarbons (CFCs) in the atmosphere affect the growth of vegetation throughout the world?

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Chlorofluorocarbons are a class of organic compounds that were used as propellants in the late 20th century. The problem with CFC's is that they attack the ozone layer, breaking it down. The weakened ozone layer is not able to stop UV light from reaching the earth, so the amount of UV light reaching the earth increases. This results in increased temperatures, and the death of vegetation.

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3 years ago

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Given the NaOH density =1.0698g mL^-1, How many mL of .71M HCl would be required to neutralize 11.33g of 2.03 M NaOH?

SSSSS [86.1K]

The volume in ml of 0.71 M HCl that would be required to neutralize 11.33 g of 2.03 M NaOH is 30.3 ml

<u><em>calculation</em></u>

Step 1 : write equation for reaction

NaOH + HCl →NaCl +H₂O

Step 2:find the volume of NaOH

volume=mass/ density

= 11.33 g/ 1.0698 g/ml =10.59 ml

Step 3: find the moles of NaOH

moles = molarity x volume in liters

molarity= 2.03 M=2.03 mol/l

volume in liters =10.59/1000 =0.0106 L

moles = 2.03 M x 0.0106 L =0.0215 moles

step 4: use the mole ratio to determine the moles of HCl

from equation in step 1 , NaOH:HCl is 1:1 therefore the moles of HCl is also 0.0215 moles

Step 5: find volume of HCl

volume= moles/ molarity

molarity =0.71 M =0.71 mol/l

=0.0215 moles /0.71 mol/l=0.0303 L

into ml =0.0303 x 1000=30.3 ml

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3 years ago

How many formula units are contained in 2.35mol of Iron (III) Oxide

konstantin123 [22]

Remember, 1 mole= 6.022x10^23 atoms, molecules, or formula units.

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3 years ago

What is the value for the kinetic energyfor a n = 2 Bohr orbit electron in Joules?

Vladimir [108]

Answer:

<u>K.E. = 5.4362 × 10⁻¹⁹ J</u>

Explanation:

The expression for Bohr velocity is:

$v=\frac{Ze^2}{2 \epsilon_0\times n\times h}$

Applying values for hydrogen atom,

Z = 1

Mass of the electron ( $m_e$ ) is 9.1093×10⁻³¹ kg

Charge of electron (e) is 1.60217662 × 10⁻¹⁹ C

$\epsilon_0$ = 8.854×10⁻¹² C² N⁻¹ m⁻²

h is Plank's constant having value = 6.626×10⁻³⁴ m² kg / s

We get that:

$v=\frac {2.185\times 10^6}{n}\ m/s$

Given, n = 2

So,

$v=\frac {2.185\times 10^6}{2}\ m/s$

$v=1.0925\times 10^6\ m/s$

Kinetic energy is:

$K.E.=\frac {1}{2}\times mv^2$

So,

$K.E.=\frac {1}{2}\times 9.1093\times 10^{-31}\times ({1.0925\times 10^6})^2$

<u>K.E. = 5.4362 × 10⁻¹⁹ J</u>

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3 years ago