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pychu [463]
3 years ago
8

How would increased chlorofluorocarbons (CFCs) in the atmosphere affect the growth of vegetation throughout the world?

Chemistry
2 answers:
IgorC [24]3 years ago
7 0
Chlorofluorocarbons are a class of organic compounds that were used as propellants in the late 20th century. The problem with CFC's is that they attack the ozone layer, breaking it down. The weakened ozone layer is not able to stop UV light from reaching the earth, so the amount of UV light reaching the earth increases. This results in increased temperatures, and the death of vegetation.

Therefore, the answer is B.
ankoles [38]3 years ago
4 0

Ultraviolet light will increase on earth's surface. It will "raise" temperatures and decrease plant populations. Actually UV rays do not increase temperature, that's wrong.

They cause mutations in several organisms as they modify their DNA. They also cause skin cancer in humans and also cataracts and sunburns.

But they don't increase temperature. That's carbon dioxide accumulation.

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Many repeating, simple subunits are joined together. What is the most likely
Hatshy [7]

Answer:

O a polymer

Explanation:

When many repeating simple subunits are joined together, this results into a polymer.

The simplest unit or smallest unit of any substance is called a monomer. When many units of a monomer joins together, a polymer results.

  • For proteins, the monomeric unit is amino-acid.
  • When they combine they form longer chain molecules called proteins.
  • For carbohydrates, the monomeric unit is called glucose.
  • When they are combined they give us a wide range of carbohydrate molecules.
6 0
3 years ago
What is the velocity of a wave traveling north with a frequency of 75 hertz and a wavelength of
Vanyuwa [196]

Answer:

v = 450 m/s

Explanation:

Given data:

Frequency = 75 Hz

Wavelength = 6 m

Velocity = ?

Solution:

Velocity is the product of frequency and wavelength.

v = f × λ

v = 75 Hz ×  6 m

Hz = s⁻¹

v = 75  s⁻¹  ×  6 m

v = 450 m/s

3 0
3 years ago
Dumbledore decides to gives a surprise demonstration. He starts with a hydrate of Na2CO3 which has a mass of 4.31 g before heati
vovikov84 [41]

Answer:

Na₂CO₃.2H₂O

Explanation:

For the hydrated compound, let us denote is by Na₂CO₃.xH₂O

The unknown is the value of x which is the amount of water of crystallisation.

Given values:

Starting mass of hydrate i.e Na₂CO₃.xH₂O = 4.31g

Mass after heating (Na₂CO₃) = 3.22g

Mass of the water of crystallisation = (4.31-3.22)g = 1.09g

To determine the integer x, we find the number of moles of the anhydrous Na₂CO₃ and that of the water of crystallisation:

        Number of moles  = \frac{mass }{molar mass }

Molar mass of Na₂CO₃ =[(23x2) + 12 + (16x3)]  = 106gmol⁻¹

Molar mass of H₂O = [(1x2) + (16)] = 18gmol⁻¹

Number of moles of Na₂CO₃ = \frac{3.22}{106} = 0.03mole

Number of moles of H₂O =  \frac{1.09}{18} = 0.06mole

From the obtained number of moles:

                          Na₂CO₃                               H₂O

                           0.03                                    0.06

Simplest

Ratio                  0.03/0.03                         0.03/0.06

                                 1                                      2

Therefore, x = 2    

7 0
3 years ago
A scientist is trying to determine whether a certain substance is radioactive. Which question would be most helpful to ask?
oksian1 [2.3K]
Well a question to ask would be if the mass of the material has changed significantly as that would determine that the substance is radioactive or if there have been any high readings found by a Geiger meter in certain period of time

hope that helps 
3 0
4 years ago
Mention the various ways by which soluble and insoluble salts are prepared
LUCKY_DIMON [66]

Answer:

Explanation:

soluble and insoluble salts are prepared by processes like neutralization reactions, simple displacement reactions and double displacement reactions.

4 0
3 years ago
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