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3 years ago

How many moles are in 454 Liters of a gas?

Chemistry

1 answer:

Natalka [10]3 years ago

3 0

Answer:

20.27 mol

Explanation:

454 L x (1 mol/22.4 L) = 20.27 mol

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The equation K + NaOH => Na + KOH should it react, true or false?

Andru [333]

Answer:

yes it should react yoyoyoyoyo

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3 years ago

A solution with a higher concentration of hydroxide ions (oh-) than hydrogen ions (h+)

Hoochie [10]

A solution with a higher concentration of hydroxide ions than hydrogen ions is basic solution.

This solution formed by Base dissolved in water and release hydroxide ions.

The PH of the solution is greater than 7

5 0

3 years ago

Which ph is more acidic, a ph of 3, a ph of 7, or a ph of 9?.

Andrei [34K]

Answer:

pH of 3.

Explanation:

pH 1 to 6 is acidic.

7 is neutral.

8 to 14 is alkaline

8 0

3 years ago

Name the cycloalkanes with molecular formula c6h12 that have a 3-membered ring and two substituents.

Tanzania [10]

Answer:

1-ethyl-2-methyl cyclopropane.

Explanation:

The structure of the molecule will be as shown in the attached image.

The molecular formula of the compound is C₆H₁₂.

It has 3 membered ring with 3 C atoms and two substituents one of them with one C atom (methyl) and the other with 2 C atoms (ethyl).

The ring consist of 3 C atoms, so its name is cyclo propane.

We numbering the atoms of the ring that give the ethyl substituent the low no. (1) and then methyl group take no. (2).

<em>Thus, the name of the compound is 1-ethyl-2-methyl cyclopropane.</em>

3 0

3 years ago

Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el

givi [52]

Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

We know that:

Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C$

$Cu^{2+}+2e^-\rightarrow Cu$

$2\times 96500=193000C$ is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

$14\times 1000g=14000g$ of copper is deposited by = $\frac{193000}{63.5}\times 14000=42551181 C$

To calculate the time required, we use the equation:

$I=\frac{q}{t}$

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

$40.0=\frac{42551181 C}{t}\\\\t=1063779sec$

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, $1063779s\times \frac{1hr}{3600s}=295hr$

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

3 0

3 years ago