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faltersainse [42]
3 years ago
8

You need a 35% alcohol solution. on hand, you have a 405 ml of a 30% alcohol mixture. you also have 80% alcohol mixture. how muc

h of the 80% mixture will you need to add to obtain the desired solution?
Chemistry
1 answer:
Bumek [7]3 years ago
4 0

You must add 45 mL of the 80 % alcohol to the 30 % alcohol to get a 35 % solution.

You can use a modified dilution formula to calculate the volume of 80 % alcohol

V1×C1 + V2×C2 = V3×C3

Let the volume of 80 % mixture 1 = <em>x</em> mL. Then the volume of the final 35 % mixture 3 = (405 + <em>x</em> ) mL

(<em>x</em> mL×80 % alc) + (405 mL×30 % alc) = (405 + <em>x</em>)mL × 35 % alc

80x + 12 150 = 14 175 + 35 x

45x = 2025

x = 2025/45 = 45

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How many atoms are in 13.97 liters of water vapor at STP
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<span>Let's </span>assume that water vapor has ideal gas behavior. <span>
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</span><span>Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol</span></span>⁻¹ K⁻¹) and T is temperature in Kelvin.<span>
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By substitution,
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Hence, number of atoms in water vapor = 0.624 mol x </span>6.022 × 10²³ mol⁻¹
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