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dalvyx [7]
3 years ago
14

Since astronauts in orbit are apparently weightless, a clever method of measuring their masses is needed to monitor their mass g

ains or losses to adjust diets. One way to do this is to exert a known force on an astronaut and measure the acceleration produced. Suppose a net external force of 50.0 N is exerted and the astronaut’s acceleration is measured to be 0.893 m/s2 . (a) Calculate her mass. (b) By exerting a force on the astronaut, the vehicle in which they orbit experiences an equal and opposite force. Discuss how this would affect the measurement of the astronaut’s acceleration. Propose a method in which recoil of the vehicle is avoided.
Physics
1 answer:
Rina8888 [55]3 years ago
7 0

Answer:

a

Her mass is m =56kg

b

The measurement of the  astronaut acceleration would be defined by relation

                a_A = \frac{m_{vehicle} a_{vehicle}}{m}

Hence it is affected by the mass of the vehicle, the acceleration of the vehicle and her mass

Now to avoid recoil on the vehicle the force on the astronaut should not be provided by the vehicle  

Explanation:

From the question we are told that

            The net external force is  F_e = 50.0N

            The astronaut's acceleration a_{A} = 0.893 m/s^2

Generally force is mathematically represented as

                            F_e = m * a_A

Where m is the mass of the astronaut

  Now making m the subject in order to obtain the mass we have

                        m = \frac{F_e}{a_A}

                            =\frac{50.0}{0.893}

                           = 56kg

Now when this force is applied it is both felt by the astronaut and the vehicle

Hence

            F_e = F_{vehicle}

=>        m * a_A = m_{vehicle} * a_{vehicle}

    This means that the measurement of the  astronaut acceleration would be defined by relation

                a_A = \frac{m_{vehicle} a_{vehicle}}{m}

             

 

 

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Answer:

The mass of the block, M =T/(3a +g)  Kg

Explanation:

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The constant force acting on the block, F₀ = Ma = 3Ma

The mass of the block, M = ?

In an Atwood's machine, the upward force of the block is given by the relation

                                     Ma = T - Mg

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                                    3Ma + Mg = T

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A certain copper wire has a resistance of 13.0 Ω . At some point along its length the wire was cut so that the resistance of one
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Answer with Explanation:

Let r be the resistance of short piece of copper wire.

Resistance of copper wire=R=13\Omega

Resistance is directly proportional to length.

If a wire has greater resistance then,the wire will be greater in length.

Therefore,resistance of long piece of wire=7r

Total resistance of copper  wire=Sum of resistance of two piece of wires

r+7r=13

8r=13

r=\frac{13}{8}ohm

Resistance of long piece of wire=7\times\frac{13}{8}=\frac{91}{8}\Omega

Resistance of short piece of wire =\frac{13}{8}\Omega

Resistivity of wire and cross section area of wire remains same .

Let L be the total  length  of wire and L' be the length of short  piece of wire.

We know that

R=\frac{\rho L}{A}=\frac{\rho}{A}L=KL

\frac{R}{L}=K

Where K=\frac{\rho}{A}=Constant

Using the formula

\frac{13}{L}=\frac{\frac{13}{8}}{L'}

\frac{L'}{L}=\frac{13}{8}\times \frac{1}{13}=\frac{1}{8}

L'=\frac{L}{8}

Length of short piece of wire=L'=\frac{L}{8}

Length of long piece of  wire=L-L'=L-\frac{L}{8}=\frac{8L-L}{8}=\frac{7}{8}L

% of length of short piece of   wire=\frac{\frac{L}{8}}{L}\times 100=12.5%%

The resistance of the short piece=\frac{13}{8}\Omega

The resistance of the long piece=\frac{91}{8}\Omega

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