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3 years ago

La) What is meant by the term Basic Quantities.

Physics

1 answer:

castortr0y [4]3 years ago

5 0

Answer:

A basic quantity is basically the physical quantity that can not be defined in terms of other quantities.

Explanation:

A basic quantity is basically the physical quantity that can not be defined in terms of other quantities.

Some of the names of the basic quantities include:

Mass, denoted by the symbol 'm', with S.I. unit 'kg'
Length, denoted by symbol 'l', with S.I. unit 'm'
Time, denoted by symbol 't', with S.I. unit 's'
Current, denoted by 'I', with S.I. unit 's' 'A'
Temperature, denoted by 'T', with S.I. unit 'K'
Amount of substance, denoted by 'n', with S.I. unit 'mol'
Luminous Intensity, denoted by 'Iv', with S.I. unit 'cd'

A basic quantity is chosen arbitrarily.

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3. What is the potential energy of a 8 Newton book sitting on a shelf that is 12 meters high?

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Answer:

P = 96 J

Explanation:

Given that,

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4 years ago

In experimental design: What are<br> the two groups?

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Answer:

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Explanation:

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In normal case, one of the two groups one is a group of subjects who get treatment known as experiment or treatment group while other group is known as control group without treatment.

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3 years ago

We have two solenoids: solenoid 2 has twice the diameter, half the length, and twice as many turns as solenoid 1. The current in

leva [86]

Answer:

the field at the center of solenoid 2 is 12 times the field at the center of solenoid 1.

Explanation:

Recall that the field inside a solenoid of length L, N turns, and a circulating current I, is given by the formula:

$B=\mu_0\, \frac{N}{L} I$

Then, if we assign the subindex "1" to the quantities that define the magnetic field ( $B_1$ ) inside solenoid 1, we have:

$B_1=\mu_0\, \frac{N_1}{L_1} I_1$

notice that there is no dependence on the diameter of the solenoid for this formula.

Now, if we write a similar formula for solenoid 2, given that it has :

1) half the length of solenoid 1 . Then $L_2=L_1/2$

2) twice as many turns as solenoid 1. Then $N_2=2\,N_1$

3) three times the current of solenoid 1. Then $I_2=3\,I_1$

we obtain:

$B_2=\mu_0\, \frac{N_2}{L_2} I_2\\B_2=\mu_0\, \frac{2\,N_1}{L_1/2} 3\,I_1\\B_2=\mu_0\, 12\,\frac{N_1}{L_1} I_1\\B_2=12\,B_1$

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4 years ago

La) What is meant by the term Basic Quantities.​

La) What is meant by the term Basic Quantities.