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3 years ago

Find the distance between points A(2, 3) and B(5, 9). Round to the nearest tenth.

Mathematics

1 answer:

castortr0y [4]3 years ago

8 0

This is the paperwork of what I did for this problem.

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Please help<br> Please also explain

schepotkina [342]

Answer: it is equal

Step-by-step explanation: you subtract 15-4 which equals 11. the exponent is the only thing being subtracted since it's a fraction. therefore it equals 10(11)

3 0

2 years ago

For what values of X are the statements below true

Galina-37 [17]

Answer:

See solutions below

Step-by-step explanation:

For what values of X are the statements below true

A. 1x>x+1

x >x+1

x-x>1

0x > 1

x > 1/0

X >∞

B) |1-x|>3

The fucntion can both be positive and negative

For the negative function

-(1-x) > 3

-1+x > 3

x > 3+1

x > 4

For the positive function

1-x > 3

-x > 3 - 1

-x > 2

x < -2

Hence the required solutions are x > 4 and x < -2

c) For the equation

|x-15| < 0

-(x - 15) < 0

-x + 15 < 0

-x < -15

x > 15

Also x-15 < 0

x < 0+15

x < 15

Hence the required solution is x > 15 and x < 15

3 0

3 years ago

On average, Tanner has noticed that 22 trains pass by his house daily (24 hours) on the nearby train tracks. What is the probabi

blondinia [14]

Answer:

0.11069

Step-by-step explanation:

We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.

P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =

${22 \choose 0} * 0.375^0*(1-0.375)^{22} + {22 \choose 1}*0.375^1*(1-0.375)^{21} +\\\\{22 \choose 2} * 0.375^2*(1-0.375)^{20} + {22 \choose 3}*0.375^3*(1-0.375)^{19} + \\{22 \choose 4} * 0.375^4*(1-0.375)^{18} + {22 \choose 5}*0.375^5*(1-0.375)^{17} = 0.11069$

I hope that works for you!

4 0

3 years ago

Given the following prescription formula, what is the ratio strength (nearest whole number) of methylcellulose in the finished p

Mamont248 [21]

Answer:

147

Step-by-step explanation:

Given:

Progesterone = 3.8 g

Glycerin = 7 mL

2% methylcellulose solution 50 mL

Cherry syrup ad = 90 mL

Now,

The total volume of the solution = 7 + 50 + 90 = 147 mL

Also,

2% methylcellulose solution 50 mL is concluded as:

the volume of methylcellulose in the solution is 2% of the total volume of the solution

thus,

volume of methylcellulose = 0.02 × 50 mL = 1 mL

Therefore,

Ratio strength of methylcellulose in the finished product

= $\frac{\textup{volume of methylcellulose}}{\textup{ total volume of the solution}}$

= $\frac{\etxtup{1}}{\textup{ 147}}$

Hence, the answer according to the question is 147

7 0

3 years ago

Whitch of the following can not be classified as a parallagrams

Sindrei [870]

Can you show the choices you have

3 0

3 years ago

Read 2 more answers