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zimovet [89]
3 years ago
14

I need help with this

Mathematics
2 answers:
Sidana [21]3 years ago
6 0
The answer is the first one
horsena [70]3 years ago
6 0

Answer:

it's 2.) -12x^8

Step-by-step explanation:

When you're multiplying two different expressions with different exponents but the same variable, you do the same thing you normally would when multiplying numbers, but you add the exponents together.

So your problem is -6x^3 * 2x^5

First step is to ignore the exponent and multiply the base numbers together:

-6 * 2

= -12

** And normally, if the two numbers just have the variable (x)  you multiply them together, and you'd get a number times x^2. And the reason this happens is bc there is always an invisible 1 exponent above a variable and you add the 1's together to make the square. When

Now add the variables and exponents (make sure to add your exponents together )

x^3+x^5

= x^8

Put your answer together add you get:

-12x^8

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9

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Resolve to me these exercises please?
Dima020 [189]
A)4^(n+3)=8^14
2^(2×(n+3))=2^(3×14)
2^(2n+6)=2^42
2^2n=2^36
n=18

b) (assuming a : is divide)
3^(2n+1)=9^17/3^3
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d) (6^n)^4×36=216^10
6^4n×6^2=6^(3×10)
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6^4n=6^28
4n=28
n=7

e)7^(n^2)÷7=49^24
7^(n^2-1)=7^(2×24)
7^(n^2)=7^49
n^2=49
n=7

g)15^(n+4)÷5^(n+4)=81^6
3^(n+4)×5^(n+4)÷5^(n+4)=3^(4×6)
3^(n+4)=3^24
n=20

h)81^n÷9^n+9^(n+2)÷9=90÷9^6
9^2n÷9^n+9^(n+2)÷9=9*10/9^6
9^n+9^(n+1)=10/9^5
I don't know where to go from here

I)what?
7 0
3 years ago
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