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Cloud [144]
3 years ago
11

How to find the area of each face of a prism

Mathematics
1 answer:
tatiyna3 years ago
3 0

If the face is a square, then (l*l)

If the face is a triangle, then (b*h)(1/2)

If the face is a rectangle, then (l*w)

If the face is a circle, then (r²)(3.14)

You can then add all these faces up to get the total surface area of the prism.

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Solve using elimination. -2x + y = 1 -6x - y = -9<br> HELP
laiz [17]

Answer:

(x,y) = (8,7)

Step-by-step explanation:

Solve equation [2] for the variable  x

 [2]    x = y + 15

Plug this in for variable  x  in equation [1]

[1]    (y +15) + y = 1

[1]    2y = -14

Solve equation [1] for the variable  y

[1]    2y = - 14

[1]    y = - 7  By now we know this much :

x = y+15

y = -7

// Use the  y  value to solve for  x

x = (-7)+15 = 8

Solution :

{x,y} = {8,-7}

5 0
3 years ago
20 points and brainliest if right!!
Ipatiy [6.2K]

Answer:

f

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Anyone got the answer?(^•^)
malfutka [58]

Answer:

It's 8

Step-by-step explanation:

16 ^{ \frac{3}{4} }  =  \sqrt[4]{16 ^{3} }  =  \sqrt[4]{2 ^{4 \times 3} } = 2^{ \frac{12}{4} }   = 2^{3}  = 8

3 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!!
dexar [7]

Peter reflecting trapezoid ABCD across the y-axis would not change the degree measurement of angle A

The degree measurement of angle A is 115 degrees

<h3>How to determine the degree measurement of angle A?</h3>

From the question, we have:

A = 115 degrees

B = 65 degrees

The transformation is a reflection across the y-axis

Reflection is a rigid transformation; and it does not change the angle measure or side lengths.

After the transformation; we have:

A = 115 degrees

B = 65 degrees

Hence, the degree measurement of angle A is 115 degrees

Read more about transformation at:

brainly.com/question/4289712

8 0
2 years ago
Plz help!!<br> Consider the given right triangle.
aalyn [17]

Answer:

b = 8

c = 16

Step-by-step explanation:

From the given right triangle,

a = 8\sqrt{3}, m(∠B) = 30°

By applying sine rule in the given triangle,

cos(B) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

cos(B) = \frac{BC}{AB}

cos(30°) = \frac{8\sqrt{3}}{c}

\frac{\sqrt{3} }{2}= \frac{8\sqrt{3} }{c}

c = 16

Further we apply tangent rule,

tan(B) = \frac{\text{Opposite side}}{\text{Adjacent side}}

tan(30°) = \frac{b}{a}

\frac{1}{\sqrt{3}}=\frac{b}{8\sqrt{3} }

b = 8

4 0
3 years ago
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