Answer: A = 58
Step-by-step explanation: The sketched region enclosed by the curves and the approximating rectangle are shown in the attachment.
From the sketches, the area will be integrated with respect to y.
To calculate the integral, first determine the limits, which will be the points where both curves meet.
In respect to y:
Finding limits:
Multiply by 2 to facilitate calculations:
Resolving quadratic equation:
y = 6 and y = -8
Then, integral to calculate area will be with limits -8<y<6:
![A = 24.6 - \frac{6^{3}}{6}-\frac{6^{2}}{2}-[24.(-8) - \frac{(-8)^{3}}{6}-\frac{(-8)^{2}}{2}]](https://tex.z-dn.net/?f=A%20%3D%2024.6%20-%20%5Cfrac%7B6%5E%7B3%7D%7D%7B6%7D-%5Cfrac%7B6%5E%7B2%7D%7D%7B2%7D-%5B24.%28-8%29%20-%20%5Cfrac%7B%28-8%29%5E%7B3%7D%7D%7B6%7D-%5Cfrac%7B%28-8%29%5E%7B2%7D%7D%7B2%7D%5D)
A = 58
<u>The area of the enclosed region is 58 square units.</u>
C. INTO SIXTHS
I LITRALLY JUST TOOK THE TEST ON EDGE. SO YOU CAN TAKE MY WORD FOR IT
<em>I HOPE I WASNT TOO LATE. IF I WAS, SORRY</em>
Answer:
you have to add them together
Answer:3.08e
Step-by-step explanation:mujwjwieekedkd
Answer:
a.) 1/2
b.) 1/8
c.) 5/8
d.) 1/2
Step-by-step explanation:
for A it is asking for probability of 1 and is 1/2 of the circle
for B it is asking for probability of 3 and it is 1/2 of and 1/4 of the circle so 1/8
for C it is asking for probability of the odd numbers and there is tow odd numbers 1 and 3 the probability of 1 is 1/2 and the probability of 3 is 1/8 adding them up will give you 5/8
for d it asks for the probability of at least 2 so therefor 2, 3, and 4 and they are 1/8 + 1/8 + for 1/4 = 1/2
