<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
3/20 = 0.15
0.15 * 100 = 15
You would need to use 15 eggs for 100 pancakes.
First make the denominators of the fractions the same by multiplying.

×

=

Now we just need to add the fractions together

=

9/6 would be the answer, but it can be simplified further, then converted into decimal form.

÷

=
=1.5 yardsYour final answer is 1.5 yards of ribbon are needed.
C. 0.4 times 6 is 2.4. Hope that helps.
Answer:
12x + 2
Step-by-step explanation:
Let the number be represented by x.
Then five times the number = 5*x
Seven times the number = 7*x
Sum of 5 times the number minus -2 =
= ![\[5x +2\]](https://tex.z-dn.net/?f=%5C%5B5x%20%2B2%5C%5D)
Adding seven times the number to this expression yields, ![\[5x+2+7x\]](https://tex.z-dn.net/?f=%5C%5B5x%2B2%2B7x%5C%5D)
![\[= (5+7)x+2\]](https://tex.z-dn.net/?f=%5C%5B%3D%20%285%2B7%29x%2B2%5C%5D)
![\[= 12x+2\]](https://tex.z-dn.net/?f=%5C%5B%3D%2012x%2B2%5C%5D)
So the simplified expression corresponds to 12x + 2.