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2 years ago

BRAINLIEST PLUS 22 POINTS

1 answer:

6 0

Hi there!

Angles that are complementary add up to 90. We know that in order to find the value of x, we'll need to create an equation. This equation would be (x + 15) + 48 = 90. This is because, together, the two angles must add up to 90.

ANSWER:
D - (x + 15) + 48 = 90

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

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At the candy store, Jonathan bought 1.74 pounds of gumdrops, 2.2 pounds of jellybeans, and 1.38 pounds of licorice. How much did

GenaCL600 [577]

Answer:

5.32 lbs

Step-by-step explanation:

add all of them together, this is common sense math you should know how to do this.

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2 years ago

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What is 2,000,000 + 6oo,oo + 2,000 + 200 + 50 + 5 in standard form

nadezda [96]

Answer:

2,602,255

Step-by-step explanation:

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2 years ago

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Here's a graph of a linear function. Write the

madam [21]

The equation of the line in slope-intercept form is y = (1/2)x + 3 and the slope is 1/2.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

$\rm m =\dfrac{y_2-y_1}{x_2-x_1}\\$

As we can see in the graph the line goes from (-6, 0) and (0, 3)

Finding the slope:

$\rm m =\dfrac{3-0}{0-(-6)}\\$

m = 3/6 = 1/2

y = mx + c

y = (1/2)x + c

c is the y-intercept

c = 3

The equation:

y = (1/2)x + 3

Thus, the equation of the line in slope-intercept form is y = (1/2)x + 3 and the slope is 1/2.

Learn more about the straight line here:

brainly.com/question/3493733

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5 0

1 year ago

Help me? idk the answer :P

Alexus [3.1K]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\
\left( 2^8\cdot 3^{-5}\cdot 6^0 \right)^{-2}\left( \cfrac{3^{-2}}{2^3} \right)^4\cdot 2^{28}\impliedby \textit{let's do the first group}
\\\\
-------------------------------\\\\
$

$\bf \left( 2^8\cdot \cfrac{1}{3^5}\cdot 1 \right)^{-2}\implies \left( \cfrac{2^8}{3^5} \right)^{-2}\implies \left( \cfrac{3^5}{2^8} \right)^{2}\implies \cfrac{3^{2\cdot 5}}{2^{2\cdot 8}}\implies \boxed{\cfrac{3^{10}}{2^{16}}}\\\\
-------------------------------\\\\
\textit{now the second group}\qquad \left( \cfrac{3^{-2}}{2^3} \right)^4\implies \left( \cfrac{\frac{1}{3^2}}{2^3} \right)^4\implies \left( \cfrac{1}{2^3\cdot 3^2} \right)^4$

$\bf \cfrac{1^4}{2^{4\cdot 3}\cdot 3^{4\cdot 2}}\implies \boxed{\cfrac{1}{2^{12}\cdot 3^8}}\\\\
-------------------------------\\\\
\textit{so we end up with\qquad }\cfrac{3^{10}}{2^{16}}\cdot \cfrac{1}{2^{12}\cdot 3^8}\cdot 2^{28}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{16}\cdot 2^{12}\cdot 3^8}
\\\\\\
\cfrac{3^{10}\cdot 2^{28}}{2^{16+12}\cdot 3^8}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{28}\cdot 3^8}\implies 3^{10}\cdot 2^{28}\cdot 2^{-28}\cdot 3^{-8}$

$\bf 3^{10-8}\cdot 2^{28-28}\implies 3^2\cdot 1\implies 3^2\implies 9$

7 0

2 years ago

6x - 8y - 5х +3y. How can you answer this

insens350 [35]

Step-by-step Solution

Problem to solve: 6x−8y−5х+3y

solving method: simplifying

Combining like terms -8yand 3y

6x−5y−5

Final Answer:

6x−5y−5

8 0

2 years ago

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