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Thepotemich [5.8K]
2 years ago
15

An inductor of inductance 0.02H and capacitor of capacitance 2 microF are connected in series to an AC source of frequency 200/p

i Hz. What is the impedance in the circuit?​
Physics
1 answer:
Ad libitum [116K]2 years ago
5 0
C because it’s not a or B so 50/50 c or d and d is def not the answer so c
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The Force Of Gravity Acting On A Childs Mass On Earth Is 490 newtons whats the childs mass
Flauer [41]
Force of gravity on an object is the weight of the object and is given by mass times accerelation due to gravity. The accerelation due to gravity is the accerelation of an object in free fall and is given by 9.8m/s^2. Given that the force of gravity acting on a child's mass on earth is 490 newtns, i.e. F = mg which means that 490 newtons = 9.8 times mass. Therefore, mass of the child is 490 / 9.8 = 50 kg.
3 0
4 years ago
Canadian nuclear reactors use heavy water moderators in which elastic collisions occur between the neutrons and deuterons of mas
ASHA 777 [7]
M*U + 0 = m*v'1 + 2m*v'2 
the zero means deuteron has no velocity
<span>where v'1 and v'2 are the post-collision velocities. 
</span>The equatio becomes
<span>U = v'1 + 2v'2</span>
<span>U = v'2- v'1 </span>
<span>v'2 = U + v'1 </span>

<span>U = v'1 + 2(U + v'1) = 2U + 3v'1 </span>
<span>U = -3V </span>
<span>V = -U / 3 </span>
<span>The speed ratio is 1/3 </span>

<span>B) Since KE is proportional to the square of the speed, if the speed is 1/3, then KE is 1/9 </span>

<span>C) (1/3)ⁿ = 1/729 </span>
<span>3ⁿ = 729 </span>
<span>n = 6 </span>
5 0
3 years ago
Read 2 more answers
Projectiles that strike objects are good examples of inelastic collisions. A 0.1 kg nail driven by a gas powered nail driver col
Ratling [72]
In an inelastic collision, only momentum is conserved, while energy is not conserved.

1) Velocity of the nail and the block after the collision
This can be found by using the total momentum after the collisions:
p_f=(m+M)v_f=4.8 kg m/s
where
m=0.1 kg is the mass of the nail
M=10 kg is the mass of the block of wood
Rearranging the formula, we find v_f, the velocity of the nail and the block after the collision:
v_f= \frac{p_f}{m+M}= \frac{4.8 kg m/s}{0.1 kg+10 kg}=  0.48 m/s

2) The velocity of the nail before the collision can be found by using the conservation of momentum. In fact, the total momentum before the collision is given only by the nail (since the block is at rest), and it must be equal to the total momentum after the collision:
p_i = mv_i = p_f
Rearranging the formula, we can find v_i, the velocity of the nail before the collision:
v_i =  \frac{p_f}{m}= \frac{4.8 kg m/s}{0.1 kg}=48 m/s
6 0
3 years ago
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What is the potential energy of a 150 kg diver standing on a diving board that is 10 m high? The potential energy is J
iris [78.8K]

The formula for potential energy would be PE = mgh Where: m is the mass; g is the acceleration due to gravity, and h would be height. So plugging in the data: PE = 150kg × 9.8 m/s^2 × 10m = 14700 Joules would be the potential energy for this problem. <span>
</span>
5 0
4 years ago
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By constructing basic electric circuits, you will be able to measure current flow. With Ohm’s law in mind, what broad question a
Bingel [31]

its all i think

thank you fam!!!! \(-u-)/

4 0
3 years ago
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