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Thepotemich [5.8K]

2 years ago

15

An inductor of inductance 0.02H and capacitor of capacitance 2 microF are connected in series to an AC source of frequency 200/p

i Hz. What is the impedance in the circuit?

1 answer:

Ad libitum [116K]2 years ago

5 0

C because it’s not a or B so 50/50 c or d and d is def not the answer so c

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Suppose that the height of the incline is h = 14.7 m. Find the speed at the bottom for each of the following objects. 1.solid sp

tensa zangetsu [6.8K]

Answer:

1. 14.4 m/s 2. 13.2 m/s 3. 12.0 m/s 4. 13.9 m/s

Explanation:

Assuming no friction present, the different objects roll without slipping, so there is a constant relationship between linear and angular velocity, as follows:

ω= v/r

If no friction exists, the change in total kinetic energy must be equal in magnitude to the change in the gravitational potential energy:

∆K = -∆U

½ *m*v² + ½* I* ω² = m*g*h

Simplifying and replacing the value of the angular velocity:

½ * v² + ½ I *(v/r)² = g*h (1)

In order to answer the question, we just need to replace h by the value given, and I (moment of inertia) for the value for each different object, as follows:

Solid Sphere I = 2/5* m *r²

Replacing in (1):

½ * v² + ½ (2/5 *m*r²) *(v/r)² = g*h

Replacing by the value given for h, and solving for v:

v = √(10/7*9.8 m/s2*14.7 m) = 14. 4 m/s

Spherical shell I=2/3*m*r²

Replacing in (1):

½ * v² + ½ (2/3 *m*r²) *(v/r)² = g*h

Replacing by the value given for h, and solving for v:

v = √(6/5*9.8 m/s2*14.7 m) = 13.2 m/s

Hoop I= m*r²

Replacing in (1):

½ * v² + ½ (m*r²) *(v/r)² = g*h

Replacing by the value given for h, and solving for v:

v = √(9.8 m/s2*14.7 m) = 12.0 m/s

Cylinder I = 1/2 * m* r²

Replacing in (1):

½ * v² + ½ (1/2 *m*r²) *(v/r)²= g*h

Replacing by the value given for h, and solving for v:

v = 2*√(1/3*9.8 m/s2*14.7 m) = 13.9 m/s

5 0

3 years ago

what is the least efficient way to roast a marshmallow using heat transfer conduction, convection, or radiation?

Kisachek [45]

Answer:

convection

Explanation:

The only way convection can only take place in liquids and gas.Since the marshmello is neither,convection is the least effective way

3 0

4 years ago

A spherical drop of water carrying a charge of 43 pC has a potential of 540 V at its surface (with V = 0 at infinity). (a) What

almond37 [142]

Explanation:

Given that,

Charge on a spherical drop of water is 43 pC

The potential at its surface is 540 V

(a) The electric potential on the surface is given by :

$V=\dfrac{kq}{r}$

r is the radius of the drop

$r=\dfrac{kq}{V}\\\\r=\dfrac{9\times 10^9\times 43\times 10^{-12}}{540}\\\\r=7.17\times 10^{-4}\ m$

(b) Let R is the radius of the spherical drop, when two such drops of the same charge and radius combine to form a single spherical drop. ATQ,

$\dfrac{4}{3}\pi r^3+\dfrac{4}{3}\pi r^3=\dfrac{4}{3}\pi R^3\\\\2r^3=R^3\\\\R=2^{1/3} r$

Now the charge on the new drop is 2q. New potential is given by :

$V=\dfrac{9\times 10^9\times 43\times 10^{-12}\times 2}{2^{1/3}\times 7.17\times 10^{-4}}\\\\V=856.79\ V$

Hence, the radius of the drop is $7.17\times 10^{-4}\ m$ and the potential at the surface of the new drop is 856.79 V.

5 0

3 years ago

Kinetic vs potential energy

antiseptic1488 [7]

Answer:

Kinetic energy is the energy obtained from movement while potential energy is the energy in something when it is at a height or has been manipulated in some way; it has work done to it.

Explanation:

Kinetic energy is, like I said, energy gained through movement or action. When an object stops moving, it converts into a different type of energy. Energy cannot be destroyed or created. An object with potential energy has a reference. A reference determines how high it is. The higher and heavier an object is, the more potential energy it has.

Hope this helps!

5 0

3 years ago

Water flows on the inside of a steel pipe with an ID of 2.5 cm. The wall thickness is 2 mm, and the convection coefficient on th

Hatshy [7]

Answer:

U = 11.67 W/m² °C

Explanation:

Inner diameter, d = 2.5 cm = 0.025 m

Thickness of the wall, t = 2 mm = 0.002 m

thus, the outer diameter, D = d + 2t = 0.025 + 2 x 0.002 = 0.029 m

$h_i =500 W/m^2.^oC$

$h_0 =12 W/m^2.^oC$

Now, based on outside convection heat transfer

we have

$\frac{1}{UA_o}=\frac{1}{h_iA_i}+\frac{1}{h_oA_o}$

on rearranging, we get

$\frac{1}{U}=\frac{1}{h_i}\frac{A_o}{A_i}+\frac{1}{h_o}$

where, $A_i\ \textup{and}\ A_o$ are the perimeter respective to inner and and outer diameter

on substituting the values, we get

$\frac{1}{U}=\frac{1}{500}\frac{0.029^2}{0.025}+\frac{1}{12}$

or

U = 11.67 W/m² °C

6 0

3 years ago