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3 years ago

Explain why it is easy to slip on a floor that is wet please, I need this answered now if anyone can.

2 answers:

5 0

It is easy to slip on a floor that is wet because there is less friction between your shoe/foot and the floor. Friction is basically when two parallel objects come in contact and form resistance. An effect of friction is the slowing down of velocity in the moving object aka your foot. This is why a rocky surface is less slippery than a marbled surface. Likewise with a west and dry surface. Hope this helps!

VladimirAG [237]3 years ago

4 0

Wet floors have less friction so there is a lesser chance of slipping. This is because the coefficient of friction μ and the therefore resultant force of limiting friction Fs is significantly reduced when a lubricant is introduced between the the two kinetic or static surfaces

You might be interested in

Calculate the torques about pivot P provided by the forces shown in the Figure 3, if L = 4.5 m

g100num [7]

The definition of torque of a force we can find the total torque on the bar is

τ = 246.2 N m

The torque of a force is defined by the relation

τ = F x r

where the bold letters indicate vectors, τ is the torque, f the force, and r the distance from the pivot point.

We can calculate the magnitude of this expression

τ = F r sin θ

where in the angle between the forces and the candidate

In this case, we have five forces

the force at point P does not create torque since its distance is zero.

The force applied to the end of the bar, the angle is zero and the sine value zero.

The other forces create a torque:

F₁ = 80 N, the distance is x₁ = 0.5L, θ₁ = 37º

F₂ = -60 N, the distance is x₂ = 0.5L, angle θ = 90º

F₃ = 70 N the distance is x₃ = L, angles θ = 30º

with respect to the vertical, this angle with respect to the horizontal is

θ’ = θ + 90

θ‘ = 30+ 90

θ₃' = 120º

substitute

τ = F₁ x₁ sin θ₁ + F₂ x₂ sin θ₂ + F₃ x₃ sin θ₃'

let's calculate

τ = 80 0.5L sin 37 - 60 0.5L sin 90 + 70 L sin 120

τ = 54.7L

indicate that the length of the bar is L + 4.5 m

τ = 54.7 4.5

τ = 246.2 Nm

Using the defined torque we can find the total torque on the bar is

τ = 246.2 N m

Learn more about torque here:

brainly.com/question/6855614

6 0

2 years ago

How do modern scientist describe the make up of matter

lbvjy [14]

The matter is a collection or composition of extremely small particles called "Atoms".

Explanation:

The matter is anything that has mass and which utilizes space by having volume.
Modern scientists describe the makeup of matter as a collection of tiny substances called atoms.
Matter can either be in solid, liquid, or gaseous state and even appear in plasma form.
Matter can neither be created nor be destroyed but only transferred from one form to the other.
Atoms are composed protons, neutrons and electrons. The protons and neutrons are contained in the nucleus, while the electrons orbit around the nucleus of the atom.
Protons are positively charged, neutrons are neutral and electrons are negative.

4 0

3 years ago

The football player throws the football with an initial diagonal velocity of 17 m/s at an

ArbitrLikvidat [17]

17 Sin (45) in the vertical and 17 Cos
(45)

8 0

3 years ago

A rope of negligible mass is wrapped around a 225-kg solid cylinder of radius 0.400 m. The cylinder is suspended several meters

vodomira [7]

Answer:

a)6.67 m/s2

b)16.7 rad/s2

c)increasing angular acceleration

Explanation:

a) It's because the system is not just mass of the man, it consists of the man holding a rope wrapped around a cylinder, not just a man free falling. So you would have to consider the rotating cylinder under the torque created by the man gravity force.

Let g = 10m/s2

T = mgd =75*10*0.4 = 300 N.m

The from the mass moments inertial of the solid cylinder:

$I = \frac{Mr^2}{2} = \frac{225*0.4^2}{2} = 18 kgm^2$

we can calculate the angular acceleration of the cylinder:

$\alpha = \frac{T}{I} = \frac{300}{18} = 16.7 rad/s^2$

then translate that to acceleration:

$a = \alpha * r = 16.7*0.4 = 6.67 m/s^2$

c) if the mass of the rope is not neglected, that means the force of gravity increases as the rope unwrapping around the cylinder, so the torque increases. Also the moment of inertial of the rope-cylinder system decreases due to rope unwrapping. In the end, the angular acceleration is no longer constant, but increasing.

4 0

3 years ago

A 16 kg science book is dropped of a 120 meter high cliff. Assuming a closed system:

Lapatulllka [165]

Answer:

Explanation:

The mass of that science book...wow. In pounds that would be 35.2! Yikes!

Anyway, we need final velocity here, and the mass of the book has nothing to do with how fast it falls. Everything is pulled by the same gravity. A feather falls at 9.8 m/s/s and so does an elephant. Mass is useless information. The equation we will use is

$v^2=v_0^2+2a$ Δx where

v is the final velocity, our unknown,

v₀ is the initial velocity which is 0 since someone had to be holding the book before dropping it,

a is the pull of gravity which is always -9.8 m/s/s, and

Δx = -120 which is the displacement (it's negative because the book falls below the point from which it was dropped). Filling in:

$v^2=0^2+2(-9.8)(-120)$ so

$v=\sqrt{2(-9.8)(-120)}$ and

v = 48 m/s

As far as how far above the bottom of the cliff the object is when it is moving at 12 m/s we will use the same equation, but the velocity will be 12:

$12^2=0^2+2(-9.8)$ Δx and

144 = -19.6Δx so

Δx = -7.3 m. That's how far from the top of the cliff it is. We subtract then t find out how far it is from the bottom:

120 - 7.3 = 112.7 m off the ground.

6 0

3 years ago