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2 years ago

Explain why it is easy to slip on a floor that is wet please, I need this answered now if anyone can.

2 answers:

5 0

It is easy to slip on a floor that is wet because there is less friction between your shoe/foot and the floor. Friction is basically when two parallel objects come in contact and form resistance. An effect of friction is the slowing down of velocity in the moving object aka your foot. This is why a rocky surface is less slippery than a marbled surface. Likewise with a west and dry surface. Hope this helps!

VladimirAG [237]2 years ago

4 0

Wet floors have less friction so there is a lesser chance of slipping. This is because the coefficient of friction μ and the therefore resultant force of limiting friction Fs is significantly reduced when a lubricant is introduced between the the two kinetic or static surfaces

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Two soccer players kick the same 1-kg ball at the same time in opposite directions. one kicks with a force of 20 n; the other ki

kolezko [41]

We can solve the problem by using Newton's second law of motion:
$\sum F = ma$ (1)
where
the term on the left is the resultant of the forces acting on an object
m is the mass of the object
a is the acceleration of the object

The mass of the ball in this problem is m=1 kg. Two forces are applied, in opposite directions, of 20 N and 12 N, therefore the resultant of the forces is
$\sum F= 20 N-12 N=8 N$

Therefore, we can rearrange eq.(1) and use these data to find the acceleration of the ball:
$a= \frac{\sum F}{m}= \frac{8 N}{1 kg}=8 m/s^2$

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3 years ago

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A brick is released with no initial speed from the roof of a building and strikes the ground in 1.80 s , encountering no appreci

Mars2501 [29]

Kinematics is used in this problem. The mass does not matter here because the question is mass independent. vi = 0 vf = x d = ? d = vi + 1/2 a t^2 d = 0 + 1/2 (9.8) (1.8)^2 d = 15.9 m (counting sig figs)

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3 years ago

An electric motor draws out 5 A of current from a 20 V battery. How much power is it using?

irinina [24]

Answer:

Explanation:

P = VI = 20(5) = 100 W

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2 years ago

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How many seconds will it take for a the International Space Station to travel 450 km at a rate of 100 m/s?

SVEN [57.7K]

Time = (distance) / (speed)

Time = (450 km) / (100 m/s)

Time = (450,000 m) / (100 m/s)

Time = 4500 seconds (that's 75 minutes)

Note:

This is about HALF the speed of the passenger jet you fly in when you go to visit Grandma for Christmas.

If the International Space Station flew at this speed, it would immediately go ker-PLUNK into the ocean.

The speed of the International Space Station in its orbit is more like 3,100 m/s, not 100 m/s.

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2 years ago

Help yet again :) A hockey player is skating on the ice at 15km/h. He shoots the puck at 138 km/h according to a radar gun on th

IceJOKER [234]

Answer:

speed of puck acc. to the radar gun = 138 km/h

speed of player = 15 km/h

since the player is in motion when he shoots, the speed of the puck will be the sum of the speed of the player and the speed at which he shot. so,

speed of puck = speed of player + speed of puck acc. to player

138 = 15 + speed of puck acc. to player

speed of puck acc. to player = 138 -15

speed of puck acc. to player = 123 km/h

Brainly this answer if you think it deserves it

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3 years ago