I think this type of equation could be conducted in simple division equation since it does not involve drop rate.
we know that there is 500 ml of substance and should be infused within 8 hours period.
So the flow rate in ml/hr would be:
500/8 = 62.5 ml/hr
Answer:
The change in length per unit length per degree rise in temperature of copper is 0.000017k
Explanation:
Given that :
The linear expansivity of copper is 0.000017k. This simply means that ; for a given copper length, the length of such copper will increase by 0.000017k for every degree rose in temperature of the copper rod.
Therefore, the change in length per unit length per degree rise in temperature (k) is 0.000017
Answer:
i. Cv =3R/2
ii. Cp = 5R/2
Explanation:
i. Cv = Molar heat capacity at constant volume
Since the internal energy of the ideal monoatomic gas is U = 3/2RT and Cv = dU/dT
Differentiating U with respect to T, we have
= d(3/2RT)/dT
= 3R/2
ii. Cp - Molar heat capacity at constant pressure
Cp = Cv + R
substituting Cv into the equation, we have
Cp = 3R/2 + R
taking L.C.M
Cp = (3R + 2R)/2
Cp = 5R/2
Answer: 5.72 x 10-3Ω
Explanation:
Hi, to answer this question, first we have to calculate the cross sectional area of the cable:
Diameter (D)=6.07 mm
Since: 1000mm = 1m
6.07mm/ 1000mm/m = 0.00607 meters
Area of a circle : π (d/2)^2
A = π (0.00607/2)^2= 0.000028937 m2
Resistance formula:
Resistance (R) = P(resistivity) L (length)÷A (cross sectional area )
Replacing with the values given:
R = (2.82x10-8 x 5.87) / 0.000028937
R = 5.72 x 10-3Ω
Feel free to ask for more if needed or if you did not understand something.
